sys.argv[1], IndexError: list index out of range [duplicate]
sys.argv
represents the command line options you execute a script with.
sys.argv[0]
is the name of the script you are running. All additional options are contained in sys.argv[1:]
.
You are attempting to open a file that uses sys.argv[1]
(the first argument) as what looks to be the directory.
Try running something like this:
python ConcatenateFiles.py /tmp
sys.argv
is the list of command line arguments passed to a Python script, where sys.argv[0]
is the script name itself.
It is erroring out because you are not passing any commandline argument, and thus sys.argv
has length 1 and so sys.argv[1]
is out of bounds.
To "fix", just make sure to pass a commandline argument when you run the script, e.g.
python ConcatenateFiles.py /the/path/to/the/directory
However, you likely wanted to use some default directory so it will still work when you don't pass in a directory:
cur_dir = sys.argv[1] if len(sys.argv) > 1 else '.'
with open(cur_dir + '/Concatenated.csv', 'w+') as outfile:
try:
with open(cur_dir + '/MatrixHeader.csv') as headerfile:
for line in headerfile:
outfile.write(line + '\n')
except:
print 'No Header File'
I've done some research and it seems that the sys.argv might require an argument at the command line when running the script
Not might, but definitely requires. That's the whole point of sys.argv
, it contains the command line arguments. Like any python array, accesing non-existent element raises IndexError
.
Although the code uses try/except
to trap some errors, the offending statement occurs in the first line.
So the script needs a directory name, and you can test if there is one by looking at len(sys.argv)
and comparing to 1+number_of_requirements. The argv always contains the script name plus any user supplied parameters, usually space delimited but the user can override the space-split through quoting. If the user does not supply the argument, your choices are supplying a default, prompting the user, or printing an exit error message.
To print an error and exit when the argument is missing, add this line before the first use of sys.argv:
if len(sys.argv)<2:
print "Fatal: You forgot to include the directory name on the command line."
print "Usage: python %s <directoryname>" % sys.argv[0]
sys.exit(1)
sys.argv[0]
always contains the script name, and user inputs are placed in subsequent slots 1, 2, ...
see also:
- sys.argv[1] meaning in script
- http://www.pythonforbeginners.com/system/python-sys-argv