Correct handling of NSJSONSerialization (try catch) in Swift (2.0)?
Solution 1:
The jsonObject
can throw
errors, so put it within do
block, use try
, and catch
any errors thrown. In Swift 3:
do {
let anyObj = try JSONSerialization.jsonObject(with: data) as! [String: Any]
let label = anyObj["label"] as! String
let value = anyObj["value"] as! Int
let uprate = anyObj["uprate"] as! Int
let sufix = anyObj["sufix"] as! String
let props = Fieldpropertie(label: label, value: value, uprate: uprate, sufix: sufix)
// etc.
} catch {
print("json error: \(error.localizedDescription)")
}
Or, in Swift 4, you can simplify your code by making your struct
conform to Codable
:
struct Fieldpropertie: Codable {
let label: String
let value: Int
let uprate: Int
let suffix: String
}
Then
do {
let props = try JSONDecoder().decode(Fieldpropertie.self, from: data)
// use props here; no manual parsing the properties is needed
} catch {
print("json error: \(error.localizedDescription)")
}
For Swift 2, see previous revision of this answer.
Solution 2:
JSONSerialization.JSONObject throws ErrorType and not NSError.
so the correct catch is
do {
let anyObj = try JSONSerialization.JSONObject(with: data, options: []) as! [String:AnyObject]
// use anyObj here
} catch let error {
print("json error: \(error)")
}
The type of error
in catch let error
is ErrorType