How to pivot rows into columns (custom pivoting)
I have a Sql Database table similar to the following:
Day Period Subject
Mon 1 Ch
Mon 2 Ph
Mon 3 Mth
Mon 4 CS
Mon 5 Lab1
Mon 6 Lab2
Mon 7 Lab3
Tue 1 Ph
Tue 2 Ele
Tue 3 Hu
Tue 4 Ph
Tue 5 En
Tue 6 CS2
Tue 7 Mth
I would like it displayed as follows: Kind of crosstab or Pivot
Day P1 P2 P3 P4 P5 P6 P7
Mon Ch Ph Mth CS2 Lab1 Lab2 Lab3
Tue Ph Ele Hu Ph En CS2 Mth
What would be the ideal way to do it? Can someone please show me the Sql code please?
You could probably do it with the PIVOT function, but I prefer the old school method:
SELECT
dy,
MAX(CASE WHEN period = 1 THEN subj ELSE NULL END) AS P1,
MAX(CASE WHEN period = 2 THEN subj ELSE NULL END) AS P2,
MAX(CASE WHEN period = 3 THEN subj ELSE NULL END) AS P3,
MAX(CASE WHEN period = 4 THEN subj ELSE NULL END) AS P4,
MAX(CASE WHEN period = 5 THEN subj ELSE NULL END) AS P5,
MAX(CASE WHEN period = 6 THEN subj ELSE NULL END) AS P6,
MAX(CASE WHEN period = 7 THEN subj ELSE NULL END) AS P7
FROM
Classes
GROUP BY
dy
ORDER BY
CASE dy
WHEN 'Mon' THEN 1
WHEN 'Tue' THEN 2
WHEN 'Wed' THEN 3
WHEN 'Thu' THEN 4
WHEN 'Fri' THEN 5
WHEN 'Sat' THEN 6
WHEN 'Sun' THEN 7
ELSE 8
END
- I changed some column names to avoid reserved words
Just incase you do want the new school method. (The Pivot statement should work in SQL2005+, the VALUES
bit for the example data only SQL2008)
WITH ExampleData AS
(
SELECT X.*
FROM (VALUES
('Mon', 1, 'Ch'),
('Mon', 2, 'Ph'),
('Mon', 3, 'Mth'),
('Mon', 4, 'CS'),
('Mon', 5, 'Lab1'),
('Mon', 6, 'Lab2'),
('Mon', 7, 'Lab3'),
('Tue', 1, 'Ph'),
('Tue', 2, 'Ele'),
('Tue', 3, 'Hu'),
('Tue', 4, 'Ph'),
('Tue', 5, 'En'),
('Tue', 6, 'CS2'),
('Tue', 7, 'Mth')
) AS X (Day, Period, Subject)
)
SELECT Day, [1] AS P1, [2] AS P2,[3] AS P3, [4] AS P4, [5] AS P5,[6] AS P6,[7] AS P7
FROM ExampleData
PIVOT
(
Max(Subject)
FOR Period IN ([1], [2],[3],[4], [5],[6], [7])
) AS PivotTable;
Result
Day P1 P2 P3 P4 P5 P6 P7
---- ---- ---- ---- ---- ---- ---- ----
Mon Ch Ph Mth CS Lab1 Lab2 Lab3
Tue Ph Ele Hu Ph En CS2 Mth