Generating permutations with repetitions
Solution 1:
You are looking for the Cartesian Product.
In mathematics, a Cartesian product (or product set) is the direct product of two sets.
In your case, this would be {1, 2, 3, 4, 5, 6}
x {1, 2, 3, 4, 5, 6}
.
itertools
can help you there:
import itertools
x = [1, 2, 3, 4, 5, 6]
[p for p in itertools.product(x, repeat=2)]
[(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3),
(2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3),
(5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)]
To get a random dice roll (in a totally inefficient way):
import random
random.choice([p for p in itertools.product(x, repeat=2)])
(6, 3)
Solution 2:
You're not looking for permutations - you want the Cartesian Product. For this use product from itertools:
from itertools import product
for roll in product([1, 2, 3, 4, 5, 6], repeat = 2):
print(roll)