Sort map by value using lambdas and streams

I'm new to Java 8, not sure how to use streams and it's methods to sort. If I have map as below, how to sort this map by value to take only top 10 entries using Java 8.

HashMap<String, Integer> map = new HashMap<String, Integer>();
        map.put("a", 10);
        map.put("b", 30);
        map.put("c", 50);
        map.put("d", 40);
        map.put("e", 100);
        map.put("f", 60);
        map.put("g", 110);
        map.put("h", 50);
        map.put("i", 90);
        map.put("k", 70);
        map.put("L", 80);

I know before Java 8, we can sort as this link: https://stackoverflow.com/a/109389/4315608

You can always start reading the documentation and some tutorials.

map.entrySet().stream()
        .sorted(Map.Entry.<String, Integer>comparingByValue().reversed()) 
        .limit(10) 
        .forEach(System.out::println); // or any other terminal method

Reference

http://www.leveluplunch.com/java/examples/sort-order-map-by-values/

See the stack flow thread here and example here

Map<String,Person> map = new HashMap<>();
map.put("g",new Person(5, "EE", 51, Person.SEX.FEMALE, "A"));
map.put("a",new Person(4, "DD", 25, Person.SEX.MALE, "D"));
map.put("e",new Person(3, "CC", 44, Person.SEX.FEMALE,"B"));

Map<String,Person> sortedNewMap = map.entrySet().stream().sorted((e1,e2)->
        e1.getValue().getLocation().compareTo(e2.getValue().getLocation()))
        .collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue,
                (e1, e2) -> e1, LinkedHashMap::new));
sortedNewMap.forEach((key,val)->{
    System.out.println(key+ " = "+ val.toString());
});

List<Map.Entry<String, Integer>> entries = newArrayList(map.entrySet());
Collections.sort(entries, (o1, o2) -> o1.getValue().compareTo(o2.getValue()));
List<Map.Entry<String, Integer>> top10 = entries.subList(0, Math.min(entries.size(), 10));