How can I generate a list of consecutive numbers?

Say if you had a number input 8 in python and you wanted to generate a list of consecutive numbers up to 8 like

[0, 1, 2, 3, 4, 5, 6, 7, 8]

How could you do this?

Solution 1:

In Python 3, you can use the builtin range function like this

>>> list(range(9))
[0, 1, 2, 3, 4, 5, 6, 7, 8]

Note 1: Python 3.x's range function, returns a range object. If you want a list you need to explicitly convert that to a list, with the list function like I have shown in the answer.

Note 2: We pass number 9 to range function because, range function will generate numbers till the given number but not including the number. So, we give the actual number + 1.

Note 3: There is a small difference in functionality of range in Python 2 and 3. You can read more about that in this answer.

Solution 2:

Using Python's built in range function:

Python 2

input = 8
output = range(input + 1)

print output
[0, 1, 2, 3, 4, 5, 6, 7, 8]

Python 3

input = 8
output = list(range(input + 1))

print(output)
[0, 1, 2, 3, 4, 5, 6, 7, 8]

Solution 3:

Here is a way to generate n consecutive numbers in equal intervals between them starting from 0 to 100 using numpy:

import numpy as np

myList = np.linspace(0, 100, n)

Solution 4:

Just to give you another example, although range(value) is by far the best way to do this, this might help you later on something else.

list = []
calc = 0

while int(calc) < 9:
    list.append(calc)
    calc = int(calc) + 1

print list
[0, 1, 2, 3, 4, 5, 6, 7, 8]