Regex split string but keep separators

I'd like to do a Regex.Split on some separators but I'd like to keep the separators. To give an example of what I'm trying:

"abc[s1]def[s2][s3]ghi" --> "abc", "[s1]", "def", "[s2]", "[s3]", "ghi"

The regular expression I've come up with is new Regex("\\[|\\]|\\]\\["). However, this gives me the following:

"abc[s1]def[s2][s3]ghi" --> "abc", "s1", "def", "s2", "", "s3", "ghi"

The separators have disappeared (which makes sense given my regex). Is there a way to write the regex so that the separators themselves are preserved?

Solution 1:

Use zero-length maching lookarounds; you want to split on

(?=\[)|(?<=\])

That is, anywhere where we assert a match of a literal [ ahead, or where we assert a match of literal ] behind.

As a C# string literal, this is

@"(?=\[)|(?<=\])"

See also

• regular-expressions.info/Lookarounds

Related questions

• Java split is eating my characters. -- has many examples

Example in Java

    System.out.println(java.util.Arrays.toString(
        "abc[s1]def[s2][s3]ghi".split("(?=\\[)|(?<=\\])")
    ));
    // prints "[abc, [s1], def, [s2], [s3], ghi]"

    System.out.println(java.util.Arrays.toString(
        "abc;def;ghi;".split("(?<=;)")
    ));
    // prints "[abc;, def;, ghi;]"

    System.out.println(java.util.Arrays.toString(
        "OhMyGod".split("(?=(?!^)[A-Z])")
    ));
    // prints "[Oh, My, God]"

Solution 2:

You could use .Matches instead of .Split, example (http://www.ideone.com/gUjRM):

string x = "abc[s1]def[s2][s3]ghi";
var r = new Regex(@"[^\[]+|\[[^\]]+\]");
var ms = r.Matches(x);
// do stuff with the MatchCollection `ms`.