g++ How to get warning on ignoring function return value
lint produces some warning like:
foo.c XXX Warning 534: Ignoring return value of function bar()
From the lint manual
534 Ignoring return value of function
'Symbol' (compare with Location) A function that returns a value is called just for side effects as, for example, in a statement by itself or the left-hand side of a comma operator. Try: (void) function(); to call a function and ignore its return value. See also the fvr, fvo and fdr flags in §5.5 "Flag Options".
I want to get this warning, if there exists any, during compilation. Is there any option in gcc/g++ to achieve this? I had turned on -Wall
but that apparently did not detect this.
Solution 1:
Thanks to WhirlWind and paxdiablo for the answer and comment. Here is my attempt to put the pieces together into a complete (?) answer.
-Wunused-result
is the relevant gcc option. And it is turned on by default. Quoting from gcc warning options page:
-Wno-unused-result
Do not warn if a caller of a function marked with attribute
warn_unused_result
(see Variable Attributes) does not use its return value. The default is-Wunused-result
So, the solution is to apply the warn_unused_result
attribute on the function.
Here is a full example. The contents of the file unused_result.c
int foo() { return 3; }
int bar() __attribute__((warn_unused_result));
int bar() { return 5; }
int main()
{
foo();
bar(); /* line 9 */
return 0;
}
and corresponding compilation result:
$gcc unused_result.c
unused_result.c: In function ‘main’:
unused_result.c:9: warning: ignoring return value of ‘bar’, declared with attribute warn_unused_result
Note again that it is not necessary to have -Wunused-result since it is default. One may be tempted to explicitly mention it to communicate the intent. Though that is a noble intent, but after analyzing the situation, my choice, however, would be against that. Because, having -Wunused-result
in the compile options may generate a false sense of security/satisfaction which is not true unless the all the functions in the code base are qualified with warn_unused_result
.
Solution 2:
Since C++17 you can use the [[nodiscard]]
attribute.
Example:
[[nodiscard]] int bar() {
return 42;
}
Solution 3:
-Wunused-result
should do this for you. This isn't one of the warnings -Wall turns on:
http://gcc.gnu.org/onlinedocs/gcc/Warning-Options.html
The function has to have the warn_unused_result attribute applied to it (Thanks paxdiablo).
Solution 4:
The answers about using __attribute__((warn_unused_result))
are correct. GCC isn't so good at this functionality, though! Be aware: it will not warn for non-POD types. That means, for example, if you return a class with a destructor (or a class with instance variables with destructors) you'll never see a warning about ignoring the result.
Relevant bug: https://gcc.gnu.org/bugzilla/show_bug.cgi?id=66177
Example where it fails:
struct Error {
~Error();
};
__attribute__((warn_unused_result)) Error test();
int main()
{
test();
return 0;
}
So, don't rely on this for return types which aren't pretty simple.