Function that is discontinuous only for integer fractions

I have this question:

Find a function $f :\mathbb R \to\mathbb R$ which is discontinuous at the points of the set $\{\frac1n : n \text{ a positive integer}\} \cup \{0\}$ but is continuous everywhere else.

I really don't know what to do. I was thinking maybe: $$ f(x) = \begin{cases} 1 \quad&\text{if }x=0 \\ 0 &\text{if } x \text{ is in } \{\tfrac1n : n \text{ a positive integer}\}\\ x &\text{otherwise} \end{cases} $$ But that kind of seems like 'cheating'. Is there a better example?

EDIT: Would it be better to have:

$$ f(x) = \begin{cases} 1 &\text{if } x \text{ is in } \{\tfrac1n : n \text{ a positive integer}\}\cup \{0\}\\ 0 &\text{otherwise} \end{cases} $$

Solution 1:

You can modify the fractional part function: $ \{x\} = \lceil x \rceil - x $, which is discontinuous at integers; to

$$ f(x) = \begin{cases} 0 & ; x = 0 \\ \left\{\dfrac{1}{x}\right\} & ; otherwise \end{cases} $$

Solution 2:

I'm going to assume your true question is finding an answer that you do not consider "cheating."

Question/Problem
Find a function $f:\mathbb{R}\to\mathbb{R}$ such that $f$ is discontinuous at each point in $K\overset{\text{def}}{=}\{\frac{1}{n}:n\in\mathbb{N}\text{ and }n\ne 0\}\cup\{0\}$ and $f$ is continuous at each point in the complement of $K$ which is denoted $(\mathbb{R}\setminus K)$

General Answer
Let $g:\mathbb{R}\to\mathbb{R}$ be an arbitrary continuous function. Let $\epsilon>0$ be an arbitrary positive real number.

Your edited answer has $g$ be the zero function and $\epsilon$ be $1$

Define $f:\mathbb{R}\to\mathbb{R}$ by $$f(x)=\begin{cases} g(x)+\epsilon&\text{if }x\in K\\ g(x)&\text{if }x\in(\mathbb{R}\setminus K) \end{cases}$$ for every $x\in\mathbb{R}$ where $K\overset{\text{def}}{=}\{\frac{1}{n}:n\in\mathbb{N}\text{ and }n\ne 0\}\cup\{0\}$.

The reason why I introduce "$K$" is because this method can be used for any given nowhere dense set $K$ where you want discontinuities. The set you were given is not special in any way for this problem. However it is a classic example of a compact set, but that's not relevant to your problem.