Checking if a NSInteger is odd or even

Solution 1:

NSInteger is defined as int (or long on some environments). So checking on oddity is like for plain int:

NSInteger num;
if (num % 2)
  // odd
else
  // even

NSInteger n = 5;

NSLog(@"%s", n & 1 ? "odd" : "even");

or using if

if (n & 1) {
  ; // odd
} else {
  ; // even
}

with some output:

if (n & 1) {
  NSLog(@"odd");
} else {
  NSLog(@"even");
}

the pointer example:

NSInteger x = 7;
NSInteger *y = &x;

if (*y & 1) {
    NSLog(@"odd");
} else {
    NSLog(@"even");
}