Print a triangular pattern of asterisks

I am required to use nested for loops and print('*', end=' ') to create the pattern shown here: enter image description here

And here is my code. I have figured out the first two.

n = 0

print ("Pattern A")
for x in range (0,11):
    n = n + 1
    for a in range (0, n-1):
        print ('*', end = '')
    print()
print ('')
print ("Pattern B")
for b in range (0,11):
    n = n - 1
    for d in range (0, n+1):
        print ('*', end = '')
    print()
print ('')

When i start pattern C and D, i try the following:

print ("Pattern C")
for e in range (11,0,-1):
    n = n + 1
    for f in range (0, n+1):
        print ('*', end = '')
    print()
print ('')
print ("Pattern D")
for g in range (11,0,-1):
    n = n - 1
    for h in range (0, n-1):
        print ('*', end = '')
    print()

But the result is the same as A and B. Help is appreciated!

Solution 1:

Both patterns C and D require leading spaces and you are not printing any spaces, just stars.

Here is alternative code that prints the required leading spaces:

print ("Pattern C")
for e in range (11,0,-1):
    print((11-e) * ' ' + e * '*')

print ('')
print ("Pattern D")
for g in range (11,0,-1):
    print(g * ' ' + (11-g) * '*')

Here is the output:

Pattern C
***********
 **********
  *********
   ********
    *******
     ******
      *****
       ****
        ***
         **
          *

Pattern D

          *
         **
        ***
       ****
      *****
     ******
    *******
   ********
  *********
 **********

In more detail, consider this line:

print((11-e) * ' ' + e * '*')

It prints (11-e) spaces followed by e stars. This provides the leading spaces needed to make the patterns.

If your teacher wants nested loops, then you may need to convert print((11-e) * ' ' + e * '*') into loops printing each space, one at a time, followed by each star, one at a time.

Pattern C via nested loops

If you followed the hints I gave about nested loops, you would have arrived at a solution for Pattern C like the following:

print ("Pattern C")
for e in range (11,0,-1):
    #print((11-e) * ' ' + e * '*')
    for d in range (11-e):
        print (' ', end = '')
    for d in range (e):
        print ('*', end = '')
    print()

Solution 2:

for i in range(1,n+1): print '{:>{}}'.format('#'*i, n)
this is For pattern D


for i in range(1,n-1): print '{:>{}}'.format('#'*i, n)
this is For pattern c

Solution 3:

Pythonic way of doing this. Just 1 line of code (using list comprehension) for each pattern.

n = 10

# for A
print('\n'.join(['*'*i for i in range(1,n+1)]))

#output
*
**
***
****
*****
******
*******
********
*********
**********


# for B
print('\n'.join(['*'*i for i in range(n+1,0,-1)]))

#output
***********
**********
*********
********
*******
******
*****
****
***
**
*

# for C
print('\n'.join([' '*(n-i) + '*'*i for i in range(n,0,-1)]))

#output
**********
 *********
  ********
   *******
    ******
     *****
      ****
       ***
        **
         *


# for D
print('\n'.join([' '*(n-i) + '*'*i for i in range(1,n+1)]))

#output
         *
        **
       ***
      ****
     *****
    ******
   *******
  ********
 *********
**********

Solution 4:

print("Pattern C")
n=int(input("Enter number of rows: ")) 
for i in range (n,0,-1):
    print((n-i) * ' ' + i * '*')