swift How to remove optional String Character

Solution 1:

Actually when you define any variable as a optional then you need to unwrap that optional value. To fix this problem either you have to declare variable as non option or put !(exclamation) mark behind the variable to unwrap the option value.

var temp : String? // This is an optional.
temp = "I am a programer"                
print(temp) // Optional("I am a programer")

var temp1 : String! // This is not optional.
temp1 = "I am a programer"
print(temp1) // "I am a programer"

Solution 2:

I looked over this again and i'm simplifying my answer. I think most the answers here are missing the point. You usually want to print whether or not your variable has a value and you also want your program not to crash if it doesn't (so don't use !). Here just do this

    print("color: \(color ?? "")")

This will give you blank or the value.

Solution 3:

You need to unwrap the optional before you try to use it via string interpolation. The safest way to do that is via optional binding:

if let color = colorChoiceSegmentedControl.titleForSegmentAtIndex(colorChoiceSegmentedControl.selectedSegmentIndex) {
    println(color) // "Red"

    let imageURLString = "http://hahaha.com/ha.php?color=\(color)"
    println(imageURLString) // http://hahaha.com/ha.php?color=Red
}

Solution 4:

Check for nil and unwrap using "!":

let color = colorChoiceSegmentedControl.titleForSegmentAtIndex(colorChoiceSegmentedControl.selectedSegmentIndex)

println(color) // Optional("Red")

if color != nil {
    println(color!) // "Red"
    let imageURLString = "http://hahaha.com/ha.php?color=\(color!)"
    println(imageURLString)
    //"http://hahaha.com/ha.php?color=Red"
}