Where do the following sequences converge pointwise and uniformly?

You can try to compare with sequences you know. For example the second one can be done using that for $n \in \mathbb{N}^{*}$ and $z=\rho e^{i\theta}$ $$ \left|\frac{z^n}{n}\right| \leq \left|\rho\right|^n=\rho^n $$ Which is a geometric sequence that you know it converges only if $\rho<1$. For uniform convergence, can you try to find the upper bound of this sequence ?

For the first one, I can give you a simple critera to check the pointwise convergence of sequences that you feel they'll converge to $0$. If a sequence $\left(a_n\right)_{n \in \mathbb{N}}$ is a sequence of strictly positive real number and if $$ \frac{a_{n+1}}{a_n}\underset{n \rightarrow +\infty}{\rightarrow}\ell <1 $$ Then the sequence converges to $0$. You can use it for the first one ( you see that it cannot tends to something else than $0$ or $\infty$ ) and for $z\ne0$ $$ \left|\frac{\left(n+1\right)z^{n+1}}{nz^n}\right|=\frac{n+1}{n}\left|z\right| \underset{n \rightarrow +\infty}{\rightarrow}\left|z\right|=\rho $$ hence if $\rho<1$ it converges to $0$. If $\rho>1$ hence $nz^n>n$ hence it diverges.

There isn't much in the way of guessing going on in, say the first one.

Just note that $$ \lim_{n\to \infty}nz^n=\infty $$ if $|z|\geq 1$ and $0$ if $|z|<1$. So you need to restrict your attention to the disc. Now, as long as you are working on a smaller disc for even just pointwise convergence, say $|z|\leq1-\delta$ for a positive $\delta$ you have $$ |nz^n|\leq n(1-\delta)^n\to0 $$ and the convergence is uniform.

If not, you have $$ n\sup_{|z|<1}|z|=n\not\to 0 $$