Iterate through 2 dimensional array

Solution 1:

Consider it as an array of arrays and this will work for sure.

int mat[][] = { {10, 20, 30, 40, 50, 60, 70, 80, 90},
                {15, 25, 35, 45},
                {27, 29, 37, 48},
                {32, 33, 39, 50, 51, 89},
              };


    for(int i=0; i<mat.length; i++) {
        for(int j=0; j<mat[i].length; j++) {
            System.out.println("Values at arr["+i+"]["+j+"] is "+mat[i][j]);
        }
    }

Solution 2:

Just invert the indexes' order like this:

for (int j = 0; j<array[0].length; j++){
     for (int i = 0; i<array.length; i++){

because all rows has same amount of columns you can use this condition j < array[0].lengt in first for condition due to the fact you are iterating over a matrix

Solution 3:

 //This is The easiest I can Imagine . 
 // You need to just change the order of Columns and rows , Yours is printing columns X rows and the solution is printing them rows X columns 
for(int rows=0;rows<array.length;rows++){
    for(int columns=0;columns <array[rows].length;columns++){
        System.out.print(array[rows][columns] + "\t" );}
    System.out.println();}

Solution 4:

Just change the indexes. i and j....in the loop, plus if you're dealing with Strings you have to use concat and initialize the variable to an empty Strong otherwise you'll get an exception.

String string="";
for (int i = 0; i<array.length; i++){
    for (int j = 0; j<array[i].length; j++){
        string = string.concat(array[j][i]);
    } 
}
System.out.println(string)