How do I open the JavaFX FileChooser from a controller class?

My problem is that all the examples of using FileChooser requires you to pass in a stage. Only problem is that my UI is defined in an fxml file, which uses a controller class separate from the main stage.

@FXML protected void locateFile(ActionEvent event) {
    FileChooser chooser = new FileChooser();
    chooser.setTitle("Open File");
    chooser.showOpenDialog(???);
}

What do I put at the ??? to make it work? Like I said, I don't have any references to any stages in the controller class, so what do I do?

Solution 1:

For any node in your scene (for example, the root node; but any node you have injected with @FXML will do), do

chooser.showOpenDialog(node.getScene().getWindow());

Solution 2:

You don't have to stick with the Stage created in the Application you can either:

@FXML protected void locateFile(ActionEvent event) {
    FileChooser chooser = new FileChooser();
    chooser.setTitle("Open File");
    File file = chooser.showOpenDialog(new Stage());
}

Or if you want to keep using the same stage then you have to pass the stage to the controller before:

    FXMLLoader loader = new FXMLLoader(getClass().getResource("yourFXMLDocument.fxml"));
    Parent root = (Parent)loader.load();
    MyController myController = loader.getController();
    myController.setStage(stage);

and you will have the main stage of the Application there to be used as you please.

Solution 3:

From a menu item

public class SerialDecoderController implements Initializable {

  @FXML
  private MenuItem fileOpen;

  @Override
  public void initialize(URL url, ResourceBundle rb) {
    // TODO
 }    


public void fileOpen (ActionEvent event) {

    FileChooser fileChooser = new FileChooser();
    fileChooser.setTitle("Open Resource File"); 
    fileChooser.showOpenDialog(fileOpen.getParentPopup().getScene().getWindow());

}