SQLAlchemy - can you add custom methods to the query object?
You can subclass the base Query
class to add your own methods:
from sqlalchemy.orm import Query
class MyQuery(Query):
def all_active(self):
return self.filter(User.is_active == True)
You then tell SQLAlchemy to use this new query class when you create the session (docs here). From your code it looks like you might be using Flask-SQLAlchemy, so you would do it as follows:
db = SQLAlchemy(session_options={'query_cls': MyQuery})
Otherwise you would pass the argument directly to the sessionmaker
:
sessionmaker(bind=engine, query_cls=MyQuery)
As of right now, this new query object isn't that interesting because we hardcoded the User
class in the method, so it won't work for anything else. A better implementation would use the query's underlying class to determine which filter to apply. This is slightly tricky but can be done as well:
class MyOtherQuery(Query):
def _get_models(self):
"""Returns the query's underlying model classes."""
if hasattr(query, 'attr'):
# we are dealing with a subquery
return [query.attr.target_mapper]
else:
return [
d['expr'].class_
for d in query.column_descriptions
if isinstance(d['expr'], Mapper)
]
def all_active(self):
model_class = self._get_models()[0]
return self.filter(model_class.is_active == True)
Finally, this new query class won't be used by dynamic relationships (if you have any). To let those also use it, you can pass it as argument when you create the relationship:
users = relationship(..., query_class=MyOtherQuery)
this work for me finely
class ParentQuery(Query):
def _get_models(self):
if hasattr(query, 'attr'):
return [query.attr.target_mapper]
else:
return self._mapper_zero().class_
def FilterByCustomer(self):
model_class = self._get_models()
return self.filter(model_class.customerId == int(g.customer.get('customerId')))
class AccountWorkflowModel(db.Model):
query_class = ParentQuery
.................