How to get name of current package in go?
Solution 1:
There is no runtime or reflect method or function that provides the functionality that you are looking for.
The closest thing I could find is:
package main
import (
"azul3d.org/lmath.v1"
"fmt"
"reflect"
)
type Empty struct{}
func main() {
fmt.Println(reflect.TypeOf(Empty{}).PkgPath())
fmt.Println(reflect.TypeOf(lmath.Vec3{0, 0, 0}).PkgPath())
}
This would output:
main
azul3d.org/lmath.v1
You could also read the first line of the file and remove the "package" substring. (Not sure if it's the best idea)
package main
import (
"bufio"
"bytes"
"fmt"
"os"
)
func main() {
file, err := os.Open("so.go")
if err != nil {
panic(err)
}
r := bufio.NewReader(file)
line, _, err := r.ReadLine()
if err != nil {
panic(err)
}
packageName := bytes.TrimPrefix(line, []byte("package "))
fmt.Println(string(packageName))
}
Solution 2:
Here a part of my logger package. It retrieves information about the caller of the logging function to show it later in the output.
func retrieveCallInfo() *callInfo {
pc, file, line, _ := runtime.Caller(2)
_, fileName := path.Split(file)
parts := strings.Split(runtime.FuncForPC(pc).Name(), ".")
pl := len(parts)
packageName := ""
funcName := parts[pl-1]
if parts[pl-2][0] == '(' {
funcName = parts[pl-2] + "." + funcName
packageName = strings.Join(parts[0:pl-2], ".")
} else {
packageName = strings.Join(parts[0:pl-1], ".")
}
return &callInfo{
packageName: packageName,
fileName: fileName,
funcName: funcName,
line: line,
}
}
As you can see it returns the package name too.
Solution 3:
To reliably get the package name, you can use the go compiler's parser to parse only the package clause.
import (
"fmt"
"go/ast"
"go/parser"
"go/token"
)
func packageName(file string) (string, error) {
fset := token.NewFileSet()
// parse the go soure file, but only the package clause
astFile, err := parser.ParseFile(fset, l.path, nil, parser.PackageClauseOnly)
if err != nil {
return "", err
}
if astFile.Name == nil {
return "", fmt.Errorf("no package name found")
}
return astFile.Name.Name, nil
}