How to strings.Split on newline?

Solution 1:

You have to use "\n".

Splitting on `\n`, searches for an actual \ followed by n in the text, not the newline byte.

playground

Solution 2:

For those of us that at times use Windows platform, it can help remember to use replace before split:

strings.Split(strings.ReplaceAll(windows, "\r\n", "\n"), "\n")

Go Playground

Solution 3:

It does not work because you're using backticks:

Raw string literals are character sequences between back quotes ``. Within the quotes, any character is legal except back quote. The value of a raw string literal is the string composed of the uninterpreted (implicitly UTF-8-encoded) characters between the quotes; in particular, backslashes have no special meaning and the string may contain newlines.

Reference: http://golang.org/ref/spec#String_literals

So, when you're doing

strings.Split(result,`\n`)

you're actually splitting using the two consecutive characters "\" and "n", and not the character of line return "\n". To do what you want, simply use "\n" instead of backticks.

Solution 4:

Your code doesn't work because you're using backticks instead of double quotes. However, you should be using a bufio.Scanner if you want to support Windows.

import (
    "bufio"
    "strings"
)
 
func SplitLines(s string) []string {
    var lines []string
    sc := bufio.NewScanner(strings.NewReader(s))
    for sc.Scan() {
        lines = append(lines, sc.Text())
    }
    return lines
}

Alternatively, you can use strings.FieldsFunc (this approach skips blank lines)

strings.FieldsFunc(s, func(c rune) bool { return c == '\n' || c == '\r' })