Unimplemented type list when trying to write.table

Solution 1:

Do this, irrespective of how many columns you have:

df <- apply(df,2,as.character)

Then do write.csv.

Solution 2:

As mentioned in the comments, you should be able to do something like this (untested) to get "flatten" your list into a character vector:

output$Title <- vapply(output$Title, paste, collapse = ", ", character(1L))

As also mentioned, if you wanted to try the unlist approach, you could "expand" each row by the individual values in output$Title, something like this:

x <- vapply(output$Title, length, 1L)          ## How many items per list element
output <- output[rep(rownames(output), x), ]   ## Expand the data frame
output$Title <- unlist(output$Title, use.names = FALSE)  ## Replace with raw values

Solution 3:

There is a new function (introduced in november 2016) in data.table package that handles writing a data.table object to csv quite well, even in those cases when a column of the data.table is a list.

fwrite(data.table, file ="myDT.csv")

Solution 4:

Another easy solution. Maybe one or more columns are of type list, so we need convert them to "character" or data frame. So there are two easy solutions

1. Convert each column "as.character" using--

   df$col1 = as.character(df$col1)

   df$col2 = as.character(df$col2)

   .......and so on

2. The best one convert df in to a "matrix"

   df = as.matrix(df)

now write df into csv. Works for me.

Solution 5:

Those are all elegant solutions.

For the curious reader who would prefer some R-code to ready made packages , here's an R-function that returns a non-list dataframe that can be exported and saved as .csv.

output is the "troublesome" data frame in question.

df_unlist<-function(df){

df<-as.data.frame(df)

nr<-nrow(df)

c.names<-colnames(df)

lscols<-as.vector(which(apply(df,2,is.list)==TRUE))

if(length(lscols)!=0){

for(i in lscols){

temp<-as.vector(unlist(df[,i]))

if(length(temp)!=nr){

adj<-nr-length(temp)

temp<-c(rep(0,adj),temp)

}

df[,i]<-temp

} #end for

df<-as.data.frame(df)

colnames(df)<-c.names
}
return(df)
}

Apply the function on dataframe "output" :

newDF<-df_unlist(output)

You can next confirm that the new (newDF) data frame is not 'listed' via apply(). This should successfully return FALSE.

apply(newDF,2,is.list)         #2 for column-wise step.

Proceed to save the new dataframe, newDF as a .csv file to a path of your choice.

write.csv(newDF,"E:/Data/newDF.csv")