Display A Popup Only Once Per User

*Note : This will show popup once per browser as the data is stored in browser memory.

Try HTML localStorage.

Methods :

• localStorage.getItem('key');
• localStorage.setItem('key','value');

$j(document).ready(function() {
    if(localStorage.getItem('popState') != 'shown'){
        $j('#popup').delay(2000).fadeIn();
        localStorage.setItem('popState','shown')
    }

    $j('#popup-close, #popup').click(function() // You are clicking the close button
    {
        $j('#popup').fadeOut(); // Now the pop up is hidden.
    });
});

Working Demo

This example uses jquery-cookie

Check if the cookie exists and has not expired - if either of those fails, then show the popup and set the cookie (Semi pseudo code):

if($.cookie('popup') != 'seen'){
    $.cookie('popup', 'seen', { expires: 365, path: '/' }); // Set it to last a year, for example.
    $j("#popup").delay(2000).fadeIn();
    $j('#popup-close').click(function(e) // You are clicking the close button
        {
        $j('#popup').fadeOut(); // Now the pop up is hiden.
    });
    $j('#popup').click(function(e) 
        {
        $j('#popup').fadeOut(); 
    });
};

You could get around this issue using php. You only echo out the code for the popup on first page load.

The other way... Is to set a cookie which is basically a file that sits in your browser and contains some kind of data. On the first page load you would create a cookie. Then every page after that you check if your cookie is set. If it is set do not display the pop up. However if its not set set the cookie and display the popup.

Pseudo code:

if(cookie_is_not_set) {
    show_pop_up;
    set_cookie;
}