Getting "bytes.Buffer does not implement io.Writer" error message
Pass a pointer to the buffer, instead of the buffer itself:
import "bufio"
import "bytes"
func main() {
var b bytes.Buffer
foo := bufio.NewWriter(&b)
}
package main
import "bytes"
import "io"
func main() {
var b bytes.Buffer
_ = io.Writer(&b)
}
You don't need use "bufio.NewWriter(&b)" to create an io.Writer. &b is an io.Writer itself.
Just use
foo := bufio.NewWriter(&b)
Because the way bytes.Buffer implements io.Writer is
func (b *Buffer) Write(p []byte) (n int, err error) {
...
}
// io.Writer definition
type Writer interface {
Write(p []byte) (n int, err error)
}
It's b *Buffer
, not b Buffer
. (I also think it is weird for we can call a method by a variable or its pointer, but we can't assign a pointer to a non-pointer type variable.)
Besides, the compiler prompt is not clear enough:
bytes.Buffer does not implement io.Writer (Write method has pointer receiver)
Some ideas, Go use Passed by value
, if we pass b
to buffio.NewWriter()
, in NewWriter(), it is a new b
(a new buffer), not the original buffer we defined, therefore we need pass the address &b
.
bytes.Buffer
is defined as:
type Buffer struct {
buf []byte // contents are the bytes buf[off : len(buf)]
off int // read at &buf[off], write at &buf[len(buf)]
bootstrap [64]byte // memory to hold first slice; helps small buffers avoid allocation.
lastRead readOp // last read operation, so that Unread* can work correctly.
}
using passed by value
, the passed new buffer struct is different from the origin buffer variable.