Check if an include (or require) exists

How do you check if an include / require_once exists before you call it, I tried putting it in an error block, but PHP didn't like that.

I think file_exists() would work with some effort, however that would require the whole file path, and a relative include could not be passed into it easily.

Are there any other ways?

I believe file_exists does work with relative paths, though you could also try something along these lines...

if(!@include("script.php")) throw new Exception("Failed to include 'script.php'");

... needless to say, you may substitute the exception for any error handling method of your choosing. The idea here is that the if-statement verifies whether the file could be included, and any error messages normally outputted by include is supressed by prefixing it with @.

Check out the stream_resolve_include_path function, it searches with the same rules as include().

http://php.net/manual/en/function.stream-resolve-include-path.php

You can also check for any variables, functions or classes defined in the include file and see if the include worked.

if (isset($variable)) { /*code*/ }

OR

if (function_exists('function_name')) { /*code*/ }

OR

if (class_exists('class_name')) { /*code*/ }

file_exists would work with checking if the required file exists when it is relative to the current working directory as it works fine with relative paths. However, if the include file was elsewhere on PATH, you would have to check several paths.

function include_exists ($fileName){
    if (realpath($fileName) == $fileName) {
        return is_file($fileName);
    }
    if ( is_file($fileName) ){
        return true;
    }

    $paths = explode(PS, get_include_path());
    foreach ($paths as $path) {
        $rp = substr($path, -1) == DS ? $path.$fileName : $path.DS.$fileName;
        if ( is_file($rp) ) {
            return true;
        }
    }
    return false;
}