Mockito verify order / sequence of method calls

InOrder helps you to do that.

ServiceClassA firstMock = mock(ServiceClassA.class);
ServiceClassB secondMock = mock(ServiceClassB.class);

Mockito.doNothing().when(firstMock).methodOne();   
Mockito.doNothing().when(secondMock).methodTwo();  

//create inOrder object passing any mocks that need to be verified in order
InOrder inOrder = inOrder(firstMock, secondMock);

//following will make sure that firstMock was called before secondMock
inOrder.verify(firstMock).methodOne();
inOrder.verify(secondMock).methodTwo();

Note that you can also use the InOrder class to verify that various methods are called in order on a single mock, not just on two or more mocks.

Suppose I have two classes Foo and Bar:

public class Foo {
  public void first() {}
  public void second() {}
}

public class Bar {
  public void firstThenSecond(Foo foo) {
    foo.first();
    foo.second();
  }
}

I can then add a test class to test that Bar's firstThenSecond() method actually calls first(), then second(), and not second(), then first(). See the following test code:

public class BarTest {
  @Test
  public void testFirstThenSecond() {
    Bar bar = new Bar();
    Foo mockFoo = Mockito.mock(Foo.class);
    bar.firstThenSecond(mockFoo);

    InOrder orderVerifier = Mockito.inOrder(mockFoo);
    // These lines will PASS
    orderVerifier.verify(mockFoo).first();
    orderVerifier.verify(mockFoo).second();

    // These lines will FAIL
    // orderVerifier.verify(mockFoo).second();
    // orderVerifier.verify(mockFoo).first();
  }
}

Yes, this is described in the documentation. You have to use the InOrder class.

Example (assuming two mocks already created):

InOrder inOrder = inOrder(serviceAMock, serviceBMock);

inOrder.verify(serviceAMock).methodOne();
inOrder.verify(serviceBMock).methodTwo();