XPath : select all following siblings until another sibling

Here is an excerpt of my xml :

<node/>
<node/>
<node id="1">content</node>
<node/>
<node/>
<node/>
<node id="2">content</node>
<node/>
<node/>

I am positioned in the node[@id='1']. I need an Xpath to match all the <node/> elements until the next not empty node (here node[@id='2']).

Edit: the @id attributes are only to explain my problem more clearly, but are not in my original XML. I need a solution which does not use the @id attributes.

I do not want to match the empty siblings after node[@id='2'], so I can't use a naive following-sibling::node[text()=''].

How can I achieve this ?

Solution 1:

You could do it this way:

../node[not(text()) and preceding-sibling::node[@id][1][@id='1']]

where '1' is the id of the current node (generate the expression dynamically).

The expression says:

• from the current context go to the parent
• select those child nodes that
• have no text and
• from all "preceding sibling nodes that have an id" the first one must have an id of 1

If you are in XSLT you can select from the following-sibling axis because you can use the current() function:

<!-- the for-each is merely to switch the current node -->
<xsl:for-each select="node[@id='1']">
  <xsl:copy-of select="
    following-sibling::node[
      not(text()) and
      generate-id(preceding-sibling::node[@id][1])
      =
      generate-id(current())
    ]
  " />
</xsl:for-each>

or simpler (and more efficient) with a key:

<xsl:key 
  name="kNode" 
  match="node[not(text())]" 
  use="generate-id(preceding-sibling::node[@id][1])"
/>

<xsl:copy-of select="key('kNode', generate-id(node[@id='1']))" />

Solution 2:

Simpler than the accepted answer:

//node[@id='1']/following-sibling::node[following::node[@id='2']]

• Find a node anywhere whose id is '1'
• Now find all the following sibling node elements
• ...but only if those elements also have a node with id="2" somewhere after them.

Shown in action with a more clear test document (and legal id values):

xml = '<root>
<node id="a"/><node id="b"/>
<node id="c">content</node>
<node id="d"/><node id="e"/><node id="f"/>
<node id="g">content</node>
<node id="h"/><node id="i"/>
</root>'

# A Ruby library that uses libxml2; http://nokogiri.org
require 'nokogiri'; doc = Nokogiri::XML(xml)

expression = "//node[@id='c']/following-sibling::node[following::node[@id='g']]"
puts doc.xpath(expression)
#=> <node id="d"/>
#=> <node id="e"/>
#=> <node id="f"/>

Solution 3:

XPath 2.0 has the operators '<<' and '>>' where node1 << node2 is true if node1 precedes node2 in document order. So based on that with XPath 2.0 in an XSLT 2.0 stylesheet where the current node is the node[@id = '1'] you could use

  following-sibling::node[not(text()) and . << current()/following-sibling::node[@od][1]]

That also needs the current() function from XSLT, so that is why I said "with XPath 2.0 in an XSLT 2.0 stylesheet". The syntax above is pure XPath, in an XSLT stylesheet you would need to escape '<<' as '&lt;&lt;'.