How can I increment a char?
In Python 2.x, just use the ord
and chr
functions:
>>> ord('c')
99
>>> ord('c') + 1
100
>>> chr(ord('c') + 1)
'd'
>>>
Python 3.x makes this more organized and interesting, due to its clear distinction between bytes and unicode. By default, a "string" is unicode, so the above works (ord
receives Unicode chars and chr
produces them).
But if you're interested in bytes (such as for processing some binary data stream), things are even simpler:
>>> bstr = bytes('abc', 'utf-8')
>>> bstr
b'abc'
>>> bstr[0]
97
>>> bytes([97, 98, 99])
b'abc'
>>> bytes([bstr[0] + 1, 98, 99])
b'bbc'
"bad enough not having a traditional for(;;) looper"?? What?
Are you trying to do
import string
for c in string.lowercase:
...do something with c...
Or perhaps you're using string.uppercase
or string.letters
?
Python doesn't have for(;;)
because there are often better ways to do it. It also doesn't have character math because it's not necessary, either.
I came from PHP, where you can increment char (A to B, Z to AA, AA to AB etc.) using ++ operator. I made a simple function which does the same in Python. You can also change list of chars to whatever (lowercase, uppercase, etc.) is your need.
# Increment char (a -> b, az -> ba)
def inc_char(text, chlist = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'):
# Unique and sort
chlist = ''.join(sorted(set(str(chlist))))
chlen = len(chlist)
if not chlen:
return ''
text = str(text)
# Replace all chars but chlist
text = re.sub('[^' + chlist + ']', '', text)
if not len(text):
return chlist[0]
# Increment
inc = ''
over = False
for i in range(1, len(text)+1):
lchar = text[-i]
pos = chlist.find(lchar) + 1
if pos < chlen:
inc = chlist[pos] + inc
over = False
break
else:
inc = chlist[0] + inc
over = True
if over:
inc += chlist[0]
result = text[0:-len(inc)] + inc
return result
Check this: USING FOR LOOP
for a in range(5):
x='A'
val=chr(ord(x) + a)
print(val)
LOOP OUTPUT: A B C D E