How to get all days in current month?

I want to get all datetime object of each day in the current month but I haven't done yet. The result expected I wanted:

[datetime.date(2014, 1, 1), datetime.date(2014, 1, 2), 
 datetime.date(2014, 1, 3), ..., datetime.date(2014, 1, 29),
 datetime.date(2014, 1, 30), datetime.date(2014, 1, 31)]

How can I solve this issue?

Please show me your ideas or suggestions. Thanks!

Here's a solution with datetime and calendar:

>>> import datetime, calendar
>>> year = 2014
>>> month = 1
>>> num_days = calendar.monthrange(year, month)[1]
>>> days = [datetime.date(year, month, day) for day in range(1, num_days+1)]
>>> days
[datetime.date(2014, 1, 1), datetime.date(2014, 1, 2), datetime.date(2014, 1, 3), datetime.date(2014, 1, 4), datetime.date(2014, 1, 5), datetime.date(2014, 1, 6), datetime.date(2014, 1, 7), datetime.date(2014, 1, 8), datetime.date(2014, 1, 9), datetime.date(2014, 1, 10), datetime.date(2014, 1, 11), datetime.date(2014, 1, 12), datetime.date(2014, 1, 13), datetime.date(2014, 1, 14), datetime.date(2014, 1, 15), datetime.date(2014, 1, 16), datetime.date(2014, 1, 17), datetime.date(2014, 1, 18), datetime.date(2014, 1, 19), datetime.date(2014, 1, 20), datetime.date(2014, 1, 21), datetime.date(2014, 1, 22), datetime.date(2014, 1, 23), datetime.date(2014, 1, 24), datetime.date(2014, 1, 25), datetime.date(2014, 1, 26), datetime.date(2014, 1, 27), datetime.date(2014, 1, 28), datetime.date(2014, 1, 29), datetime.date(2014, 1, 30), datetime.date(2014, 1, 31)]

Look into calendar module:

import calendar
print calendar.monthcalendar(2013, 4)
[[1, 2, 3, 4, 5, 6, 7], [8, 9, 10, 11, 12, 13, 14], [15, 16, 17, 18, 19, 20, 21], [22, 23, 24, 25, 26, 27, 28], [29, 30, 0, 0, 0, 0, 0]]

Using datetime and timedelta:

import datetime
d0 = datetime.datetime(year=2014, month=1, day=1)
d1 = datetime.datetime(year=2014, month=2, day=1)
print (d1 - d0).days
>>> 31

There are several methods, but with calendar.monthrange, you can get a tuple (first_weekday, nb_days):

>>> from calendar import monthrange
>>> monthrange(2014, 2)
(5, 28)
>>> a = monthrange(2014, 2)
>>> range(1, a[1]+1)
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28]
>>> [datetime.date(2014, 2, day) for day in range(1, a[1]+1)]
[datetime.date(2014, 1, 1), datetime.date(2014, 1, 2), datetime.date(2014, 1, 3), datetime.date(2014, 1, 4), datetime.date(2014, 1, 5), datetime.date(2014, 1, 6), datetime.date(2014, 1, 7), datetime.date(2014, 1, 8), datetime.date(2014, 1, 9), datetime.date(2014, 1, 10), datetime.date(2014, 1, 11), datetime.date(2014, 1, 12), datetime.date(2014, 1, 13), datetime.date(2014, 1, 14), datetime.date(2014, 1, 15), datetime.date(2014, 1, 16), datetime.date(2014, 1, 17), datetime.date(2014, 1, 18), datetime.date(2014, 1, 19), datetime.date(2014, 1, 20), datetime.date(2014, 1, 21), datetime.date(2014, 1, 22), datetime.date(2014, 1, 23), datetime.date(2014, 1, 24), datetime.date(2014, 1, 25), datetime.date(2014, 1, 26), datetime.date(2014, 1, 27), datetime.date(2014, 1, 28), datetime.date(2014, 1, 29), datetime.date(2014, 1, 30), datetime.date(2014, 1, 31)]

With a function to make it cleaner:

from calendar import monthrange
import datetime

def get_datetime_range(year, month):
    nb_days = monthrange(year, month)[1]

    return [datetime.date(year, month, day) for day in range(1, nb_days+1)]

print get_datetime_range(2014, 2)  # usage example

How to get all days in current month?

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