How to wait until an element is present in Selenium?

Solution 1:

You need to call ignoring with exception to ignore while the WebDriver will wait.

FluentWait<WebDriver> fluentWait = new FluentWait<>(driver)
        .withTimeout(30, TimeUnit.SECONDS)
        .pollingEvery(200, TimeUnit.MILLISECONDS)
        .ignoring(NoSuchElementException.class);

See the documentation of FluentWait for more info. But beware that this condition is already implemented in ExpectedConditions so you should use

WebElement element = (new WebDriverWait(driver, 10))
   .until(ExpectedConditions.elementToBeClickable(By.id("someid")));

*Update for newer versions of Selenium:

withTimeout(long, TimeUnit) has become withTimeout(Duration)
pollingEvery(long, TimeUnit) has become pollingEvery(Duration)

So the code will look as such:

FluentWait<WebDriver> fluentWait = new FluentWait<>(driver)
        .withTimeout(Duration.ofSeconds(30)
        .pollingEvery(Duration.ofMillis(200)
        .ignoring(NoSuchElementException.class);

Basic tutorial for waiting can be found here.

Solution 2:

WebDriverWait wait = new WebDriverWait(driver,5)
wait.until(ExpectedConditions.visibilityOf(element));

you can use this as some time before loading whole page code gets executed and throws and error. time is in second

Solution 3:

Let me recommend you using Selenide library. It allows writing much more concise and readable tests. It can wait for presence of elements with much shorter syntax:

$("#elementId").shouldBe(visible);

Here is a sample project for testing Google search: https://github.com/selenide-examples/google