Creating a Generic<T> type instance with a variable containing the Type
Is it possible to achieve the following code? I know it doesn't work, but I'm wondering if there is a workaround?
Type k = typeof(double);
List<k> lst = new List<k>();
Yes, there is:
var genericListType = typeof(List<>);
var specificListType = genericListType.MakeGenericType(typeof(double));
var list = Activator.CreateInstance(specificListType);
A cleaner way might be to use a generic method. Do something like this:
static void AddType<T>()
where T : DataObject
{
Indexes.Add(typeof(T), new Dictionary<int, T>());
}