Python conversion from binary string to hexadecimal

int given base 2 and then hex:

>>> int('010110', 2)
22
>>> hex(int('010110', 2))
'0x16'
>>> 

>>> hex(int('0000010010001101', 2))
'0x48d'

The doc of int:

int(x[, base]) -> integer

Convert a string or number to an integer, if possible.  A floating

point argument will be truncated towards zero (this does not include a string representation of a floating point number!) When converting a string, use the optional base. It is an error to supply a base when converting a non-string. If base is zero, the proper base is guessed based on the string content. If the argument is outside the integer range a long object will be returned instead.

The doc of hex:

hex(number) -> string

Return the hexadecimal representation of an integer or long

integer.

bstr = '0000 0100 1000 1101'.replace(' ', '')
hstr = '%0*X' % ((len(bstr) + 3) // 4, int(bstr, 2))

Use python's binascii module

import binascii

binFile = open('somebinaryfile.exe','rb')
binaryData = binFile.read(8)

print binascii.hexlify(binaryData)

Converting Binary into hex without ignoring leading zeros:

You could use the format() built-in function like this:

"{0:0>4X}".format(int("0000010010001101", 2))

Using no messy concatenations and padding :

'{:0{width}x}'.format(int(temp,2)), width=4)

Will give a hex representation with padding preserved