glob exclude pattern

I have a directory with a bunch of files inside: eee2314, asd3442 ... and eph.

I want to exclude all files that start with eph with the glob function.

How can I do it?

The pattern rules for glob are not regular expressions. Instead, they follow standard Unix path expansion rules. There are only a few special characters: two different wild-cards, and character ranges are supported [from pymotw: glob – Filename pattern matching].

So you can exclude some files with patterns.
For example to exclude manifests files (files starting with _) with glob, you can use:

files = glob.glob('files_path/[!_]*')

You can deduct sets:

set(glob("*")) - set(glob("eph*"))

You can't exclude patterns with the glob function, globs only allow for inclusion patterns. Globbing syntax is very limited (even a [!..] character class must match a character, so it is an inclusion pattern for every character that is not in the class).

You'll have to do your own filtering; a list comprehension usually works nicely here:

files = [fn for fn in glob('somepath/*.txt') 
         if not os.path.basename(fn).startswith('eph')]