How to check that a string is an int, but not a double, etc.?
PHP has an intval()
function that will convert a string to an integer. However I want to check that the string is an integer beforehand, so that I can give a helpful error message to the user if it's wrong. PHP has is_int()
, but that returns false for string like "2"
.
PHP has the is_numeric()
function, but that will return true if the number is a double. I want something that will return false for a double, but true for an int.
e.g.:
my_is_int("2") == TRUE
my_is_int("2.1") == FALSE
Solution 1:
How about using ctype_digit
?
From the manual:
<?php
$strings = array('1820.20', '10002', 'wsl!12');
foreach ($strings as $testcase) {
if (ctype_digit($testcase)) {
echo "The string $testcase consists of all digits.\n";
} else {
echo "The string $testcase does not consist of all digits.\n";
}
}
?>
The above example will output:
The string 1820.20 does not consist of all digits. The string 10002 consists of all digits. The string wsl!12 does not consist of all digits.
This will only work if your input is always a string:
$numeric_string = '42';
$integer = 42;
ctype_digit($numeric_string); // true
ctype_digit($integer); // false
If your input might be of type int
, then combine ctype_digit
with is_int
.
If you care about negative numbers, then you'll need to check the input for a preceding -
, and if so, call ctype_digit
on a substr
of the input string. Something like this would do it:
function my_is_int($input) {
if ($input[0] == '-') {
return ctype_digit(substr($input, 1));
}
return ctype_digit($input);
}
Solution 2:
filter_var
should do it:
var_dump(filter_var('2', FILTER_VALIDATE_INT)); // 2
var_dump(filter_var('2.0', FILTER_VALIDATE_INT)); // false
var_dump(filter_var('2.1', FILTER_VALIDATE_INT)); // false
but
var_dump(filter_var(2, FILTER_VALIDATE_INT)); // 2
var_dump(filter_var(2.0, FILTER_VALIDATE_INT)); // 2
var_dump(filter_var(2.1, FILTER_VALIDATE_INT)); // false
If you just want Booleans as return values, wrap it into a function, e.g.
function validatesAsInt($number)
{
$number = filter_var($number, FILTER_VALIDATE_INT);
return ($number !== FALSE);
}
Solution 3:
+1 to Dominic's answer (using ctype_digit
). Another way you could do it is with type coercion:
$inty = "2";
$inty2 = " 2";
$floaty = "2.1";
$floaty2 = "2.0";
is_int($inty + 0); // true
is_int($floaty + 0); // false
is_int($floaty2 + 0); // false
// here's difference between this and the ctype functions.
is_int($inty2 + 0); // true
ctype_digit($inty2); // false
Solution 4:
Cast it to int. if it still have the same value its int;
function my_is_int($var) {
$tmp = (int) $var;
if($tmp == $var)
return true;
else
return false;
}
Solution 5:
One really clean way that I like to use is that one. You cast it twice, first in int
, secondly in string
, then you strict compare ===
. See the example below:
$value === (string)(int)$value;
Now, about your function my_is_int, you can do something like this:
function my_is_int($value){ return $value === (string)(int)$value; }
my_is_int('2'); // true
my_is_int('2.1') // false