How to determine if a string is a valid v4 UUID? [duplicate]
Version 4 UUIDs have the form xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx
where x
is any hexadecimal digit and y
is one of 8
, 9
, A
, or B
.
^[0-9A-F]{8}-[0-9A-F]{4}-4[0-9A-F]{3}-[89AB][0-9A-F]{3}-[0-9A-F]{12}$
To allow lowercase letters, use i
modifier →
$UUIDv4 = '/^[0-9A-F]{8}-[0-9A-F]{4}-4[0-9A-F]{3}-[89AB][0-9A-F]{3}-[0-9A-F]{12}$/i';
preg_match($UUIDv4, $value) or die('Not valid UUID');
I found this question while I was looking for a Python answer. To help people in the same situation, I've added the Python solution.
You can use the uuid
module:
#!/usr/bin/env python
from uuid import UUID
def is_valid_uuid(uuid_to_test, version=4):
"""
Check if uuid_to_test is a valid UUID.
Parameters
----------
uuid_to_test : str
version : {1, 2, 3, 4}
Returns
-------
`True` if uuid_to_test is a valid UUID, otherwise `False`.
Examples
--------
>>> is_valid_uuid('c9bf9e57-1685-4c89-bafb-ff5af830be8a')
True
>>> is_valid_uuid('c9bf9e58')
False
"""
try:
uuid_obj = UUID(uuid_to_test, version=version)
except ValueError:
return False
return str(uuid_obj) == uuid_to_test
if __name__ == '__main__':
import doctest
doctest.testmod()
All the existing answers use regex. If you're using Python, you might want to consider a try/except
in case you don't want to use regex:
(Bit shorter than the answer above).
Our validator would then be:
import uuid
def is_valid_uuid(val):
try:
uuid.UUID(str(val))
return True
except ValueError:
return False
>>> is_valid_uuid(1)
False
>>> is_valid_uuid("123-UUID-wannabe")
False
>>> is_valid_uuid({"A":"b"})
False
>>> is_valid_uuid([1, 2, 3])
False
>>> is_valid_uuid(uuid.uuid4())
True
>>> is_valid_uuid(str(uuid.uuid4()))
True
>>> is_valid_uuid(uuid.uuid4().hex)
True
>>> is_valid_uuid(uuid.uuid3(uuid.NAMESPACE_DNS, 'example.net'))
True
>>> is_valid_uuid(uuid.uuid5(uuid.NAMESPACE_DNS, 'example.net'))
True
>>> is_valid_uuid("{20f5484b-88ae-49b0-8af0-3a389b4917dd}")
True
>>> is_valid_uuid("20f5484b88ae49b08af03a389b4917dd")
True