How do I check if a number is a palindrome?

For any given number:

n = num;
rev = 0;
while (num > 0)
{
    dig = num % 10;
    rev = rev * 10 + dig;
    num = num / 10;
}

If n == rev then num is a palindrome:

cout << "Number " << (n == rev ? "IS" : "IS NOT") << " a palindrome" << endl;

This is one of the Project Euler problems. When I solved it in Haskell I did exactly what you suggest, convert the number to a String. It's then trivial to check that the string is a pallindrome. If it performs well enough, then why bother making it more complex? Being a pallindrome is a lexical property rather than a mathematical one.

def ReverseNumber(n, partial=0):
    if n == 0:
        return partial
    return ReverseNumber(n // 10, partial * 10 + n % 10)

trial = 123454321
if ReverseNumber(trial) == trial:
    print("It's a Palindrome!")

Works for integers only. It's unclear from the problem statement if floating point numbers or leading zeros need to be considered.