What does "TypeError: 'float' object cannot be interpreted as an integer" mean when using range?
In:
for i in range(c/10):
You're creating a float as a result - to fix this use the int division operator:
for i in range(c // 10):
range()
can only work with integers, but dividing with the /
operator always results in a float value:
>>> 450 / 10
45.0
>>> range(450 / 10)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'float' object cannot be interpreted as an integer
Make the value an integer again:
for i in range(int(c / 10)):
or use the //
floor division operator:
for i in range(c // 10):
As shown below, range
only supports integers:
>>> range(15.0)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: range() integer end argument expected, got float.
>>> range(15)
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14]
>>>
However, c/10
is a float because /
always returns a float.
Before you put it in range
, you need to make c/10
an integer. This can be done by putting it in int
:
range(int(c/10))
or by using //
, which returns an integer:
range(c//10)
It is also possible to fix this with np.arange()
instead of range which works for float numbers:
import numpy as np
for i in np.arange(c/10):