Check if string contains a value in array [duplicate]

Solution 1:

Try this.

$string = 'my domain name is website3.com';
foreach ($owned_urls as $url) {
    //if (strstr($string, $url)) { // mine version
    if (strpos($string, $url) !== FALSE) { // Yoshi version
        echo "Match found"; 
        return true;
    }
}
echo "Not found!";
return false;

Use stristr() or stripos() if you want to check case-insensitive.

Solution 2:

Try this:

$owned_urls= array('website1.com', 'website2.com', 'website3.com');

$string = 'my domain name is website3.com';

$url_string = end(explode(' ', $string));

if (in_array($url_string,$owned_urls)){
    echo "Match found"; 
    return true;
} else {
    echo "Match not found";
    return false;
}

- Thanks

Solution 3:

This was a lot easier to do if all you want to do is find a string in an array.

$array = ["they has mystring in it", "some", "other", "elements"];
if (stripos(json_encode($array),'mystring') !== false) {
echo "found mystring";
}

Solution 4:

Simple str_replace with count parameter would work here:

$count = 0;
str_replace($owned_urls, '', $string, $count);
// if replace is successful means the array value is present(Match Found).
if ($count > 0) {
  echo "One of Array value is present in the string.";
}

More Info - https://www.techpurohit.com/extended-behaviour-explode-and-strreplace-php