jQuery: get the file name selected from <input type="file" />

This code should work in IE (don't even test it in Firefox), but it doesn't. What I want is to display the name of the attached file. Any help?

<html>
<head>
  <title>example</title>    
  <script type="text/javascript" src="../js/jquery.js"></script>
  <script type="text/javascript">  
        $(document).ready( function(){            
      $("#attach").after("<input id='fakeAttach' type='button' value='attach a file' />");      
      $("#fakeAttach").click(function() {            
        $("#attach").click();        
        $("#maxSize").after("<div id='temporary'><span id='attachedFile'></span><input id='remove' type='button' value='remove' /></div>");        
        $('#attach').change(function(){
          $("#fakeAttach").attr("disabled","disabled");          
          $("#attachedFile").html($(this).val());
        });        
        $("#remove").click(function(e){
          e.preventDefault();
          $("#attach").replaceWith($("#attach").clone());
          $("#fakeAttach").attr("disabled","");
          $("#temporary").remove();
        });
      })
    }); 
  </script> 
</head>
<body>
  <input id="attach" type="file" /><span id="maxSize">(less than 1MB)</span>    
</body>
</html>

Solution 1:

It is just such simple as writing:

$('input[type=file]').val()

Anyway, I suggest using name or ID attribute to select your input. And with event, it should look like this:

$('input[type=file]').change(function(e){
  $in=$(this);
  $in.next().html($in.val());
});

Solution 2:

The simplest way is to simply use the following line of jquery, using this you don't get the /fakepath nonsense, you straight up get the file that was uploaded:

$('input[type=file]')[0].files[0]; // This gets the file
$('#idOfFileUpload')[0].files[0]; // This gets the file with the specified id

Some other useful commands are:

To get the name of the file:

$('input[type=file]')[0].files[0].name; // This gets the file name

To get the type of the file:

If I were to upload a PNG, it would return image/png

$("#imgUpload")[0].files[0].type

To get the size (in bytes) of the file:

$("#imgUpload")[0].files[0].size

Also you don't have to use these commands on('change', you can get the values at any time, for instance you may have a file upload and when the user clicks upload, you simply use the commands I listed.