Send e-mail to Gmail with inline image using Python
Solution 1:
It seems that following the gmail email template works:
* multipart/alternative
- text/plain
- multipart/related
+ text/html
<img src="cid:msgid"/>
+ image/png
Content-ID: <msgid>
Based on the example from email
module docs:
#!/usr/bin/env python3
import html
import mimetypes
from email.headerregistry import Address
from email.message import EmailMessage
from email.utils import make_msgid
from pathlib import Path
title = 'Picture report…'
path = Path('TESTING.png')
me = Address("Pepé Le Pew", *gmail_user.rsplit('@', 1))
msg = EmailMessage()
msg['Subject'] = 'Report…'
msg['From'] = me
msg['To'] = [me]
msg.set_content('[image: {title}]'.format(title=title)) # text/plain
cid = make_msgid()[1:-1] # strip <>
msg.add_alternative( # text/html
'<img src="cid:{cid}" alt="{alt}"/>'
.format(cid=cid, alt=html.escape(title, quote=True)),
subtype='html')
maintype, subtype = mimetypes.guess_type(str(path))[0].split('/', 1)
msg.get_payload()[1].add_related( # image/png
path.read_bytes(), maintype, subtype, cid="<{cid}>".format(cid=cid))
# save to disk a local copy of the message
Path('outgoing.msg').write_bytes(bytes(msg))
To send msg
via gmail:
import smtplib
import ssl
with smtplib.SMTP('smtp.gmail.com', timeout=10) as s:
s.starttls(context=ssl.create_default_context())
s.login(gmail_user, gmail_password)
s.send_message(msg)
Python 2/3 compatible version
* multipart/related
- multipart/alternative
+ text/plain
+ text/html
<div dir="ltr"><img src="cid:ii_xyz" alt="..."><br></div>
- image/jpeg
Content-ID: <ii_xyz>
Based on Send an HTML email with embedded image and plain text alternate:
#!/usr/bin/env python
# -*- coding: utf-8 -*-
import cgi
import uuid
import os
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.image import MIMEImage
from email.header import Header
img = dict(title=u'Picture report…', path=u'TESTING.png', cid=str(uuid.uuid4()))
msg = MIMEMultipart('related')
msg['Subject'] = Header(u'Report…', 'utf-8')
msg['From'] = gmail_user
msg['To'] = ", ".join([to])
msg_alternative = MIMEMultipart('alternative')
msg.attach(msg_alternative)
msg_text = MIMEText(u'[image: {title}]'.format(**img), 'plain', 'utf-8')
msg_alternative.attach(msg_text)
msg_html = MIMEText(u'<div dir="ltr">'
'<img src="cid:{cid}" alt="{alt}"><br></div>'
.format(alt=cgi.escape(img['title'], quote=True), **img),
'html', 'utf-8')
msg_alternative.attach(msg_html)
with open(img['path'], 'rb') as file:
msg_image = MIMEImage(file.read(), name=os.path.basename(img['path']))
msg.attach(msg_image)
msg_image.add_header('Content-ID', '<{}>'.format(img['cid']))
To send msg
via gmail:
import ssl
s = SMTP_SSL('smtp.gmail.com', timeout=10,
ssl_kwargs=dict(cert_reqs=ssl.CERT_REQUIRED,
ssl_version=ssl.PROTOCOL_TLSv1,
# http://curl.haxx.se/ca/cacert.pem
ca_certs='cacert.pem'))
s.set_debuglevel(0)
try:
s.login(gmail_user, gmail_pwd)
s.sendmail(msg['From'], [to], msg.as_string())
finally:
s.quit()
SMTP_SSL
is optional, you could use starttls
method from your question instead:
import smtplib
import socket
import ssl
import sys
class SMTP_SSL(smtplib.SMTP_SSL):
"""Add support for additional ssl options."""
def __init__(self, host, port=0, **kwargs):
self.ssl_kwargs = kwargs.pop('ssl_kwargs', {})
self.ssl_kwargs['keyfile'] = kwargs.pop('keyfile', None)
self.ssl_kwargs['certfile'] = kwargs.pop('certfile', None)
smtplib.SMTP_SSL.__init__(self, host, port, **kwargs)
def _get_socket(self, host, port, timeout):
if self.debuglevel > 0:
print>>sys.stderr, 'connect:', (host, port)
new_socket = socket.create_connection((host, port), timeout)
new_socket = ssl.wrap_socket(new_socket, **self.ssl_kwargs)
self.file = getattr(smtplib, 'SSLFakeFile', lambda x: None)(new_socket)
return new_socket
Solution 2:
I think you need to add the following lines:
from email.mime.image import MIMEImage
body = MIMEText('<p>Test Image<img src="cid:testimage" /></p>', _subtype='html')
msg.attach(body)
img = MIMEImage(image.read(), 'jpeg')
img.add_header('Content-Id', '<testimage>')
msg.attach(img)
testimage
should be replaced with a unique identifier