git clone and checkout in a single command

The following is the command I use to checkout a specific commit.

git clone git://repo.git/repo123
git checkout <commitID>

I want to do the above in one step - using a git clone command only.

The reason why I want to do this is, repo123 is very huge. So checking out the commit I want will save me a lot of time.

I am aware of --depth option. But in this case, it is of no use. Can anyone tell me how to do it?

git clone u://r/l --branch x

still clones everything but sets the local HEAD to that branch so it's the one checked out.

Source:

--branch <name>
-b <name>
Instead of pointing the newly created HEAD to the branch pointed to by the cloned repository’s HEAD, point to <name> branch instead. In a non-bare repository, this is the branch that will be checked out. --branch can also take tags and detaches the HEAD at that commit in the resulting repository.

Is your problem the checkout being to large or the repository itself? As git clone, well, clones a repository you usually get the whole repository in its full size. (unless you are doing a shallow clone as you already suggested.)

If it's really about the checkout of the wrong branch git help clone says:

   --no-checkout, -n
       No checkout of HEAD is performed after the clone is complete.

After cloning with -n you can manually check out