passing functor as function pointer
You cannot directly pass a pointer to a C++ functor object as a function pointer to C code (or even to C++ code).
Additionally, to portably pass a callback to C code it needs to be at least declared
as an extern "C"
non-member function.
At least, because some APIs require specific function call conventions and thus
additional declaration modifiers.
In many environments C and C++ have the same calling conventions and differ only
in name mangling, so any global function or static member will work.
But you still need to wrap the call to operator()
in a normal function.
-
If your functor has no state (it is an object just to satisfy some formal requirements etc):
class MyFunctor { // no state public: MyFunctor(); int operator()(SomeType ¶m) const; }
you can write a normal extern "C" function which creates the functor and executes its operator().
extern "C" int MyFunctorInC(SomeType *param) { static MyFunctor my_functor; return my_functor(*param); }
-
If your functor has state, eg:
class MyFunctor { // Some fields here; public: MyFunctor(/* some parameters to set state */); int operator()(SomeType ¶m) const; // + some methods to retrieve result. }
and the C callback function takes some kind of user state parameter (usually void *):
void MyAlgorithmInC(SomeType *arr, int (*fun)(SomeType *, void *), void *user_state);
you can write a normal extern "C" function which casts its state parameter to your functor object:
extern "C" int MyFunctorInC(SomeType *param, void *user_state) { MyFunctor *my_functor = (MyFunctor *)user_state; return (*my_functor)(*param); }
and use it like this:
MyFunctor my_functor(/* setup parameters */); MyAlgorithmInC(input_data, MyFunctorInC, &my_functor);
Otherwise the only normal way to do it (normal as in "without generating machine code at runtime" etc.) is to use some static (global) or thread local storage to pass the functor to an extern "C" function. This limits what you can do with your code and is ugly but will work.
I found this "gem" using google. Apparently possible but I sure wouldn't recommend it. Direct link to example source code.
No, of course. The signature of your C function take an argument as function.
void f(void (*func)())
{
func(); // Only void f1(), void F2(), ....
}
All tricks with functors are used by template functions:
template<class Func>
void f (Func func)
{
func(); // Any functor
}