Build tree array from flat array in javascript

There is an efficient solution if you use a map-lookup. If the parents always come before their children you can merge the two for-loops. It supports multiple roots. It gives an error on dangling branches, but can be modified to ignore them. It doesn't require a 3rd-party library. It's, as far as I can tell, the fastest solution.

function list_to_tree(list) {
  var map = {}, node, roots = [], i;
  
  for (i = 0; i < list.length; i += 1) {
    map[list[i].id] = i; // initialize the map
    list[i].children = []; // initialize the children
  }
  
  for (i = 0; i < list.length; i += 1) {
    node = list[i];
    if (node.parentId !== "0") {
      // if you have dangling branches check that map[node.parentId] exists
      list[map[node.parentId]].children.push(node);
    } else {
      roots.push(node);
    }
  }
  return roots;
}

var entries = [{
    "id": "12",
    "parentId": "0",
    "text": "Man",
    "level": "1",
    "children": null
  },
  {
    "id": "6",
    "parentId": "12",
    "text": "Boy",
    "level": "2",
    "children": null
  },
  {
    "id": "7",
    "parentId": "12",
    "text": "Other",
    "level": "2",
    "children": null
  },
  {
    "id": "9",
    "parentId": "0",
    "text": "Woman",
    "level": "1",
    "children": null
  },
  {
    "id": "11",
    "parentId": "9",
    "text": "Girl",
    "level": "2",
    "children": null
  }
];

console.log(list_to_tree(entries));

If you're into complexity theory this solution is Θ(n log(n)). The recursive-filter solution is Θ(n^2) which can be a problem for large data sets.


( BONUS1 : NODES MAY or MAY NOT BE ORDERED )

( BONUS2 : NO 3RD PARTY LIBRARY NEEDED, PLAIN JS )

( BONUS3 : User "Elias Rabl" says this is the most performant solution, see his answer below )

Here it is:

const createDataTree = dataset => {
  const hashTable = Object.create(null);
  dataset.forEach(aData => hashTable[aData.ID] = {...aData, childNodes: []});
  const dataTree = [];
  dataset.forEach(aData => {
    if(aData.parentID) hashTable[aData.parentID].childNodes.push(hashTable[aData.ID])
    else dataTree.push(hashTable[aData.ID])
  });
  return dataTree;
};

Here is a test, it might help you to understand how the solution works :

it('creates a correct shape of dataTree', () => {
  const dataSet = [{
    "ID": 1,
    "Phone": "(403) 125-2552",
    "City": "Coevorden",
    "Name": "Grady"
  }, {
    "ID": 2,
    "parentID": 1,
    "Phone": "(979) 486-1932",
    "City": "Chełm",
    "Name": "Scarlet"
  }];

  const expectedDataTree = [{
    "ID": 1,
    "Phone": "(403) 125-2552",
    "City": "Coevorden",
    "Name": "Grady",
    childNodes: [{
      "ID": 2,
      "parentID": 1,
      "Phone": "(979) 486-1932",
      "City": "Chełm",
      "Name": "Scarlet",
      childNodes : []
    }]
  }];

  expect(createDataTree(dataSet)).toEqual(expectedDataTree);
});

As mentioned by @Sander, @Halcyon`s answer assumes a pre-sorted array, the following does not. (It does however assume you have loaded underscore.js - though it could be written in vanilla javascript):

Code

// Example usage
var arr = [
    {'id':1 ,'parentid' : 0},
    {'id':2 ,'parentid' : 1},
    {'id':3 ,'parentid' : 1},
    {'id':4 ,'parentid' : 2},
    {'id':5 ,'parentid' : 0},
    {'id':6 ,'parentid' : 0},
    {'id':7 ,'parentid' : 4}
];

unflatten = function( array, parent, tree ){
    tree = typeof tree !== 'undefined' ? tree : [];
    parent = typeof parent !== 'undefined' ? parent : { id: 0 };
        
    var children = _.filter( array, function(child){ return child.parentid == parent.id; });
    
    if( !_.isEmpty( children )  ){
        if( parent.id == 0 ){
           tree = children;   
        }else{
           parent['children'] = children
        }
        _.each( children, function( child ){ unflatten( array, child ) } );                    
    }
    
    return tree;
}

tree = unflatten( arr );
document.body.innerHTML = "<pre>" + (JSON.stringify(tree, null, " "))
<script src="https://cdnjs.cloudflare.com/ajax/libs/underscore.js/1.9.1/underscore-min.js"></script>

Requirements

It assumes the properties 'id' and 'parentid' indicate ID and parent ID respectively. There must be elements with parent ID 0, otherwise you get an empty array back. Orphaned elements and their descendants are 'lost'

http://jsfiddle.net/LkkwH/1/


Use this ES6 approach. Works like charm

// Data Set
// One top level comment 
const comments = [{
    id: 1,
    parent_id: null
}, {
    id: 2,
    parent_id: 1
}, {
    id: 3,
    parent_id: 1
}, {
    id: 4,
    parent_id: 2
}, {
    id: 5,
    parent_id: 4
}];

const nest = (items, id = null, link = 'parent_id') =>
  items
    .filter(item => item[link] === id)
    .map(item => ({ ...item, children: nest(items, item.id) }));

console.log(
  nest(comments)
)

Had the same problem, but I could not be certain that the data was sorted or not. I could not use a 3rd party library so this is just vanilla Js; Input data can be taken from @Stephen's example;

 var arr = [
        {'id':1 ,'parentid' : 0},
        {'id':4 ,'parentid' : 2},
        {'id':3 ,'parentid' : 1},
        {'id':5 ,'parentid' : 0},
        {'id':6 ,'parentid' : 0},
        {'id':2 ,'parentid' : 1},
        {'id':7 ,'parentid' : 4},
        {'id':8 ,'parentid' : 1}
      ];
    function unflatten(arr) {
      var tree = [],
          mappedArr = {},
          arrElem,
          mappedElem;

      // First map the nodes of the array to an object -> create a hash table.
      for(var i = 0, len = arr.length; i < len; i++) {
        arrElem = arr[i];
        mappedArr[arrElem.id] = arrElem;
        mappedArr[arrElem.id]['children'] = [];
      }


      for (var id in mappedArr) {
        if (mappedArr.hasOwnProperty(id)) {
          mappedElem = mappedArr[id];
          // If the element is not at the root level, add it to its parent array of children.
          if (mappedElem.parentid) {
            mappedArr[mappedElem['parentid']]['children'].push(mappedElem);
          }
          // If the element is at the root level, add it to first level elements array.
          else {
            tree.push(mappedElem);
          }
        }
      }
      return tree;
    }

var tree = unflatten(arr);
document.body.innerHTML = "<pre>" + (JSON.stringify(tree, null, " "))

JS Fiddle

Flat Array to Tree