Find point at distance d perpendicular to endpoint A of given line segment AB

geometry linear-algebra

I would use the angles, get the slope of the line as follows: $$ \theta = \arctan\frac{y_B-y_A}{x_B-x_A} $$ Then the coordinates of $A_2$ would be $$ x_{A_2} = x_A+d \cos(90+\theta) \\ y_{A_2} = y_A+d \sin(90+\theta) $$

Related

Proving limit doesn't exist using the $\epsilon$-$\delta$ definition
excel vba: copy rows if data match with values in column in another sheet
How can I update my OpenGL to 3.0 or higher
windows can't find .exe when i make a batch file
Basic question about proofs with the goal $\exists x P(x)$
Computer stops working after 5 minutes of use in windows
Proof (confusion) of the product of two random variables of two sequences converge to XY
Do people sometimes get blocked by a webservice for things someone else has done with their dynamic IP-Address [closed]
Edges on an even number of Hamilton cycles
Finding limits $l=\lim_{x \rightarrow a}\frac{x^x-a^x}{x-a} $ & $m= \lim_{x \rightarrow a}\frac{a^x-x^a}{x-a} $.
Proof that the Casimir invariant of a representation commutes with everything
Convert flat array to the multi-dimensional