Real mouse position in canvas
I'm trying to draw with the mouse over a HTML5 canvas, but the only way that it seems to work well is if the canvas is in the position 0,0 (upper left corner) if I change the canvas position, for some reason it doesn't draw like it should. Here is my code.
function createImageOnCanvas(imageId){
document.getElementById("imgCanvas").style.display = "block";
document.getElementById("images").style.overflowY= "hidden";
var canvas = document.getElementById("imgCanvas");
var context = canvas.getContext("2d");
var img = new Image(300,300);
img.src = document.getElementById(imageId).src;
context.drawImage(img, (0),(0));
}
function draw(e){
var canvas = document.getElementById("imgCanvas");
var context = canvas.getContext("2d");
posx = e.clientX;
posy = e.clientY;
context.fillStyle = "#000000";
context.fillRect (posx, posy, 4, 4);
}
The HTML part
<body>
<div id="images">
</div>
<canvas onmousemove="draw(event)" style="margin:0;padding:0;" id="imgCanvas"
class="canvasView" width="250" height="250"></canvas>
I have read there's a way of creating a simple function in JavaScript to get the right position, but I have no idea about how to do it.
Solution 1:
The Simple 1:1 Scenario
For situations where the canvas element is 1:1 compared to the bitmap size, you can get the mouse positions by using this snippet:
function getMousePos(canvas, evt) {
var rect = canvas.getBoundingClientRect();
return {
x: evt.clientX - rect.left,
y: evt.clientY - rect.top
};
}
Just call it from your event with the event and canvas as arguments. It returns an object with x and y for the mouse positions.
As the mouse position you are getting is relative to the client window you'll have to subtract the position of the canvas element to convert it relative to the element itself.
Example of integration in your code:
//put this outside the event loop..
var canvas = document.getElementById("imgCanvas");
var context = canvas.getContext("2d");
function draw(evt) {
var pos = getMousePos(canvas, evt);
context.fillStyle = "#000000";
context.fillRect (pos.x, pos.y, 4, 4);
}
Note: borders and padding will affect position if applied directly to the canvas element so these needs to be considered via getComputedStyle() - or apply those styles to a parent div instead.
When Element and Bitmap are of different sizes
When there is the situation of having the element at a different size than the bitmap itself, for example, the element is scaled using CSS or there is pixel-aspect ratio etc. you will have to address this.
Example:
function getMousePos(canvas, evt) {
var rect = canvas.getBoundingClientRect(), // abs. size of element
scaleX = canvas.width / rect.width, // relationship bitmap vs. element for X
scaleY = canvas.height / rect.height; // relationship bitmap vs. element for Y
return {
x: (evt.clientX - rect.left) * scaleX, // scale mouse coordinates after they have
y: (evt.clientY - rect.top) * scaleY // been adjusted to be relative to element
}
}
With transformations applied to context (scale, rotation etc.)
Then there is the more complicated case where you have applied transformation to the context such as rotation, skew/shear, scale, translate etc. To deal with this you can calculate the inverse matrix of the current matrix.
Newer browsers let you read the current matrix via the currentTransform property and Firefox (current alpha) even provide a inverted matrix through the mozCurrentTransformInverted. Firefox however, via mozCurrentTransform, will return an Array and not DOMMatrix as it should. Neither Chrome, when enabled via experimental flags, will return a DOMMatrix but a SVGMatrix.
In most cases however you will have to implement a custom matrix solution of your own (such as my own solution here - free/MIT project) until this get full support.
When you eventually have obtained the matrix regardless of path you take to obtain one, you'll need to invert it and apply it to your mouse coordinates. The coordinates are then passed to the canvas which will use its matrix to convert it to back wherever it is at the moment.
This way the point will be in the correct position relative to the mouse. Also here you need to adjust the coordinates (before applying the inverse matrix to them) to be relative to the element.
An example just showing the matrix steps
function draw(evt) {
var pos = getMousePos(canvas, evt); // get adjusted coordinates as above
var imatrix = matrix.inverse(); // get inverted matrix somehow
pos = imatrix.applyToPoint(pos.x, pos.y); // apply to adjusted coordinate
context.fillStyle = "#000000";
context.fillRect(pos.x-1, pos.y-1, 2, 2);
}
An example of using currentTransform when implemented would be:
var pos = getMousePos(canvas, e); // get adjusted coordinates as above
var matrix = ctx.currentTransform; // W3C (future)
var imatrix = matrix.invertSelf(); // invert
// apply to point:
var x = pos.x * imatrix.a + pos.y * imatrix.c + imatrix.e;
var y = pos.x * imatrix.b + pos.y * imatrix.d + imatrix.f;
Update I made a free solution (MIT) to embed all these steps into a single easy-to-use object that can be found here and also takes care of a few other nitty-gritty things most ignore.
Solution 2:
You can get the mouse positions by using this snippet:
function getMousePos(canvas, evt) {
var rect = canvas.getBoundingClientRect();
return {
x: (evt.clientX - rect.left) / (rect.right - rect.left) * canvas.width,
y: (evt.clientY - rect.top) / (rect.bottom - rect.top) * canvas.height
};
}
This code takes into account both changing coordinates to canvas space (evt.clientX - rect.left) and scaling when canvas logical size differs from its style size (/ (rect.right - rect.left) * canvas.width see: Canvas width and height in HTML5).
Example: http://jsfiddle.net/sierawski/4xezb7nL/
Source: jerryj comment on http://www.html5canvastutorials.com/advanced/html5-canvas-mouse-coordinates/