How to select id with max date group by category in PostgreSQL?

Solution 1:

This is a perfect use-case for DISTINCT ON - a Postgres specific extension of the standard DISTINCT:

SELECT DISTINCT ON (category)
       id  -- , category, date  -- any other column (expression) from the same row
FROM   tbl
ORDER  BY category, date DESC;

Careful with descending sort order. If the column can be NULL, you may want to add NULLS LAST:

• Sort by column ASC, but NULL values first?

DISTINCT ON is simple and fast. Detailed explanation in this related answer:

• Select first row in each GROUP BY group?

For big tables with many rows per category consider an alternative approach:

• Optimize GROUP BY query to retrieve latest row per user
• Optimize groupwise maximum query

Solution 2:

Try this one:

SELECT t1.* FROM Table1 t1
JOIN 
(
   SELECT category, MAX(date) AS MAXDATE
   FROM Table1
   GROUP BY category
) t2
ON T1.category = t2.category
AND t1.date = t2.MAXDATE

See this SQLFiddle

Solution 3:

Another approach is to use the first_value window function: http://sqlfiddle.com/#!12/7a145/14

SELECT DISTINCT
  first_value("id") OVER (PARTITION BY "category" ORDER BY "date" DESC) 
FROM Table1
ORDER BY 1;

... though I suspect hims056's suggestion will typically perform better where appropriate indexes are present.

A third solution is:

SELECT
  id
FROM (
  SELECT
    id,
    row_number() OVER (PARTITION BY "category" ORDER BY "date" DESC) AS rownum
  FROM Table1
) x
WHERE rownum = 1;