One liner: creating a dictionary from list with indices as keys
a = [51,27,13,56]
b = dict(enumerate(a))
print(b)
will produce
{0: 51, 1: 27, 2: 13, 3: 56}
enumerate(sequence, start=0)Return an enumerate object. sequence must be a sequence, an iterator, or some other object which supports iteration. The
next()method of the iterator returned byenumerate()returns atuplecontaining a count (from start which defaults to 0) and the values obtained from iterating over sequence:
With another constructor, you have
a = [51,27,13,56] #given list
d={i:x for i,x in enumerate(a)}
print(d)