Integer solutions for $\frac{1}{x^2}+\frac{1}{y^2}=\frac{1}{z^2}$?

number-theory diophantine-equations

Solution 1:

For the equation.

$$\frac{1}{x^2}+\frac{1}{y^2}=\frac{1}{z^2}$$

Use a Pythagorean triple.

$$a^2+b^2=c^2$$

Obtained solutions.

$$x=ac$$

$$y=bc$$

$$z=ab$$

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