No analytic function in $\{|z|<1\}$ such that $f(0)=1$ and $|f(z)|\ge 1+|z|^2$. Proof strategy
Solution 1:
Your proof is alright. You assumed the existence of a function $f$ with the given properties and derived a contradiction.
Your proof is alright. You assumed the existence of a function $f$ with the given properties and derived a contradiction.