How to write a Java program which can extract a JAR file and store its data in specified directory (location)?

Solution 1:

Adapt this example: How to extract Java resources from JAR and zip archive

Or try this code:

Extract the Contents of ZIP/JAR Files Programmatically

Suppose jarFile is the jar/zip file to be extracted. destDir is the path where it will be extracted:

java.util.jar.JarFile jar = new java.util.jar.JarFile(jarFile);
java.util.Enumeration enumEntries = jar.entries();
while (enumEntries.hasMoreElements()) {
    java.util.jar.JarEntry file = (java.util.jar.JarEntry) enumEntries.nextElement();
    java.io.File f = new java.io.File(destDir + java.io.File.separator + file.getName());
    if (file.isDirectory()) { // if its a directory, create it
        f.mkdir();
        continue;
    }
    java.io.InputStream is = jar.getInputStream(file); // get the input stream
    java.io.FileOutputStream fos = new java.io.FileOutputStream(f);
    while (is.available() > 0) {  // write contents of 'is' to 'fos'
        fos.write(is.read());
    }
    fos.close();
    is.close();
}
jar.close();

Source: http://www.devx.com/tips/Tip/22124

Solution 2:

You can use this code snippet as a reference to get your task done.Its almost the same as the code snippet shown above by @JuanZe except that for those who were getting the FileNotFoundException, i have added a small code snippet that will check if the file does exist and if it doesn't then it will create the parent folder along with the files and will extract the contents of jar file inside the specified destination folder.

Code snippet:

public class JarDemo {

  public static void main(String[] args) throws java.io.IOException {
    java.util.jar.JarFile jarfile = new java.util.jar.JarFile(new java.io.File("E:/sqljdbc4.jar")); //jar file path(here sqljdbc4.jar)
    java.util.Enumeration<java.util.jar.JarEntry> enu= jarfile.entries();
    while(enu.hasMoreElements())
    {
        String destdir = "E:/abc/";     //abc is my destination directory
        java.util.jar.JarEntry je = enu.nextElement();

        System.out.println(je.getName());

        java.io.File fl = new java.io.File(destdir, je.getName());
        if(!fl.exists())
        {
            fl.getParentFile().mkdirs();
            fl = new java.io.File(destdir, je.getName());
        }
        if(je.isDirectory())
        {
            continue;
        }
        java.io.InputStream is = jarfile.getInputStream(je);
        java.io.FileOutputStream fo = new java.io.FileOutputStream(fl);
        while(is.available()>0)
        {
            fo.write(is.read());
        }
        fo.close();
        is.close();
    }

  }

}

Solution 3:

JarFile class.

JarFile file = new JarFile("file.jar");   
for (Enumeration<JarEntry> enum = file.entries(); enum.hasMoreElements();) {   
    JarEntry entry = enum.next();   
    System.out.println(entry.getName());   
} 

Solution 4:

Here is what I would do to extract my whole "resources" folder from my jar. It is way more faster to use BufferedReader and BufferedWriter.

 public static boolean extractResourcesToTempFolder() {
    try {
        //If folder exist, delete it.
        String destPath = getTempDir() + File.separator + "JToolkit" + File.separator;
        deleteDirectoryRecursive(new File(destPath));            

        JarFile jarFile = new JarFile(JToolkit.class.getProtectionDomain().getCodeSource().getLocation().getPath());
        Enumeration<JarEntry> enums = jarFile.entries();
        while (enums.hasMoreElements()) {
            JarEntry entry = enums.nextElement();
            if (entry.getName().startsWith("resources")) {
                File toWrite = new File(destPath + entry.getName());
                if (entry.isDirectory()) {
                    toWrite.mkdirs();
                    continue;
                }
                InputStream in = new BufferedInputStream(jarFile.getInputStream(entry));
                OutputStream out = new BufferedOutputStream(new FileOutputStream(toWrite));
                byte[] buffer = new byte[2048];
                for (;;) {
                    int nBytes = in.read(buffer);
                    if (nBytes <= 0) {
                        break;
                    }
                    out.write(buffer, 0, nBytes);
                }
                out.flush();
                out.close();
                in.close();
            }
            System.out.println(entry.getName());
        }
    } catch (IOException ex) {
        Logger.getLogger(Methods.class.getName()).log(Level.SEVERE, null, ex);
        return false;
    }
    return true;
}

Solution 5:

Old question.
Here is a updated answer using :

• Java 7 java.nio to create and copy efficiently entries
• Java 8 stream to sort and collect the entries lexicographically (in order to always create folders first).

Note that I used java.util.zip.ZipFile (the base class) instead of java.util.jar.JarFile (the subclass).
The last one performs more things that are not required to "just" extract files from an archive.
So it reduces the overhead and prevents exception rising related to security concerns. But if required you can of course replace ZipFile/ZipEntry by JarFile/JarEntry.

import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Path;
import java.util.Comparator;
import java.util.List;
import java.util.stream.Collectors;
import java.util.zip.ZipEntry;
import java.util.zip.ZipFile;

public class FileUtils {

    public static void extractArchive(Path archiveFile, Path destPath) throws IOException {

        Files.createDirectories(destPath); // create dest path folder(s)

        try (ZipFile archive = new ZipFile(archiveFile.toFile())) {

            // sort entries by name to always create folders first
            List<? extends ZipEntry> entries = archive.stream()
                                                      .sorted(Comparator.comparing(ZipEntry::getName))
                                                      .collect(Collectors.toList());

            // copy each entry in the dest path
            for (ZipEntry entry : entries) {
                Path entryDest = destPath.resolve(entry.getName());

                if (entry.isDirectory()) {
                    Files.createDirectory(entryDest);
                    continue;
                }

                Files.copy(archive.getInputStream(entry), entryDest);
            }
        }

    }
}