Python - Finding word frequencies of list of words in text file
I am trying to speed up my project to count word frequencies. I have 360+ text files, and I need to get the total number of words and the number of times each word from another list of words appears. I know how to do this with a single text file.
>>> import nltk
>>> import os
>>> os.chdir("C:\Users\Cameron\Desktop\PDF-to-txt")
>>> filename="1976.03.txt"
>>> textfile=open(filename,"r")
>>> inputString=textfile.read()
>>> word_list=re.split('\s+',file(filename).read().lower())
>>> print 'Words in text:', len(word_list)
#spits out number of words in the textfile
>>> word_list.count('inflation')
#spits out number of times 'inflation' occurs in the textfile
>>>word_list.count('jobs')
>>>word_list.count('output')
Its too tedious to get the frequencies of 'inflation', 'jobs', 'output' individual. Can I put these words into a list and find the frequency of all the words in the list at the same time? Basically this with Python.
Example: Instead of this:
>>> word_list.count('inflation')
3
>>> word_list.count('jobs')
5
>>> word_list.count('output')
1
I want to do this (I know this isn't real code, this is what I'm asking for help on):
>>> list1='inflation', 'jobs', 'output'
>>>word_list.count(list1)
'inflation', 'jobs', 'output'
3, 5, 1
My list of words is going to have 10-20 terms, so I need to be able to just point Python toward a list of words to get the counts of. It would also be nice if the output was able to be copy+paste into an excel spreadsheet with the words as columns and frequencies as rows
Example:
inflation, jobs, output
3, 5, 1
And finally, can anyone help automate this for all of the textfiles? I figure I just point Python toward the folder and it can do the above word counting from the new list for each of the 360+ text files. Seems easy enough, but I'm a bit stuck. Any help?
An output like this would be fantastic: Filename1 inflation, jobs, output 3, 5, 1
Filename2
inflation, jobs, output
7, 2, 4
Filename3
inflation, jobs, output
9, 3, 5
Thanks!
collections.Counter() has this covered if I understand your problem.
The example from the docs would seem to match your problem.
# Tally occurrences of words in a list
cnt = Counter()
for word in ['red', 'blue', 'red', 'green', 'blue', 'blue']:
cnt[word] += 1
print cnt
# Find the ten most common words in Hamlet
import re
words = re.findall('\w+', open('hamlet.txt').read().lower())
Counter(words).most_common(10)
From the example above you should be able to do:
import re
import collections
words = re.findall('\w+', open('1976.03.txt').read().lower())
print collections.Counter(words)
EDIT naive approach to show one way.
wanted = "fish chips steak"
cnt = Counter()
words = re.findall('\w+', open('1976.03.txt').read().lower())
for word in words:
if word in wanted:
cnt[word] += 1
print cnt
One possible implementation (using Counter)...
Instead of printing the output, I think it would be simpler to write to a csv file and import that into Excel. Look at http://docs.python.org/2/library/csv.html and replace print_summary
.
import os
from collections import Counter
import glob
def word_frequency(fileobj, words):
"""Build a Counter of specified words in fileobj"""
# initialise the counter to 0 for each word
ct = Counter(dict((w, 0) for w in words))
file_words = (word for line in fileobj for word in line.split())
filtered_words = (word for word in file_words if word in words)
return Counter(filtered_words)
def count_words_in_dir(dirpath, words, action=None):
"""For each .txt file in a dir, count the specified words"""
for filepath in glob.iglob(os.path.join(dirpath, '*.txt')):
with open(filepath) as f:
ct = word_frequency(f, words)
if action:
action(filepath, ct)
def print_summary(filepath, ct):
words = sorted(ct.keys())
counts = [str(ct[k]) for k in words]
print('{0}\n{1}\n{2}\n\n'.format(
filepath,
', '.join(words),
', '.join(counts)))
words = set(['inflation', 'jobs', 'output'])
count_words_in_dir('./', words, action=print_summary)