Can local and register variables be declared extern?
Local variables can be declared extern in some cases
Let's read the C99 N1256 standard draft.
The standard calls "local variables" as having "block scope".
6.7.1/5 "Storage-class specifiers" says:
The declaration of an identifier for a function that has block scope shall have no explicit storage-class specifier other than extern.
Then for what it means to add extern
to a local variable, 6.2.2/4 "Linkages of identifiers" says:
For an identifier declared with the storage-class specifier extern in a scope in which a prior declaration of that identifier is visible, if the prior declaration specifies internal or external linkage, the linkage of the identifier at the later declaration is the same as the linkage specified at the prior declaration. If no prior declaration is visible, or if the prior declaration specifies no linkage, then the identifier has external linkage.
Lets break down those cases.
no prior declaration
void f() {
extern int i;
}
is the same as:
extern int i;
void f() {}
except that the declaration is only visible inside f
.
This is because i
has no prior declaration visible. So i
has external linkage (the same linkage as global variables).
prior declaration specifies no linkage
int i;
void f() {
extern int i;
}
is the same as:
void f() {
extern int i;
}
because the prior declaration int i
specifies no linkage because paragraph 6 says:
The following identifiers have no linkage: an identifier declared to be anything other than an object or a function; an identifier declared to be a function parameter; a block scope identifier for an object declared without the storage-class specifier extern.
prior declaration specifies internal or external linkage
extern int i;
void f() {
extern int i;
}
is the same as:
extern int i;
void f() {}
and:
static int i;
void f() {
extern int i;
}
is the same as:
static int i;
void f() {}
because in both cases we have a previous visible external and internal (static
) linkage declarations respectively.
Initialize local extern
Invalid C:
void f() {
extern int i = 0;
}
because the block scope declaration has an initialization.
Valid C:
extern int i = 0;
void f() {}
but arguably bad style because equivalent to the shorter:
int i = 0;
void f() {}
because 6.7.8 Initialization says:
If the declaration of an identifier has block scope, and the identifier has external or internal linkage, the declaration shall have no initializer for the identifier.
- Can local variables be declared extern?
No. But a global variable can be declared extern
locally.
// file1.c
int Count;
// file2.c
void foo(void) {
extern int Count;
Count++;
}
- Can register variables be declared extern?
No. A variable may not be extern
and register
.
C11 dr 6.7.1 Storage-class specifiers
1 storage-class-specifier:typedef
extern
static
_Thread_local
auto
register
Constraints
2 At most, one storage-class specifier may be given in the declaration specifiers in a declaration, except that_Thread_local
may appear withstatic
orextern
)
6.9 External definitions of C99 states:
The storage-class specifiers auto and register shall not appear in the declaration specifiers in an external declaration.