Shell script to capture Process ID and kill it if exist [duplicate]

I tried this code and it is not working

#!/bin/sh

#Find the Process ID for syncapp running instance

PID=`ps -ef | grep syncapp 'awk {print $2}'`

if [[ -z "$PID" ]] then
Kill -9 PID
fi

It is showing a error near awk.

Any suggestions please.

Actually the easiest way to do that would be to pass kill arguments like below:

ps -ef | grep your_process_name | grep -v grep | awk '{print $2}' | xargs kill

Hope it helps.

This works good for me.

PID=`ps -eaf | grep syncapp | grep -v grep | awk '{print $2}'`
if [[ "" !=  "$PID" ]]; then
  echo "killing $PID"
  kill -9 $PID
fi

I use the command pkill for this:

NAME
       pgrep, pkill - look up or signal processes based on name and 
       other attributes

SYNOPSIS
       pgrep [options] pattern
       pkill [options] pattern

DESCRIPTION
       pgrep looks through the currently running processes and lists 
       the process IDs which match the selection criteria to stdout.
       All the criteria have to match.  For example,

              $ pgrep -u root sshd

       will only list the processes called sshd AND owned by root.
       On the other hand,

              $ pgrep -u root,daemon

       will list the processes owned by root OR daemon.

       pkill will send the specified signal (by default SIGTERM) 
       to each process instead of listing them on stdout.

If your code runs via interpreter (java, python, ...) then the name of the process is the name of the interpreter. You need to user the argument --full. This matches against the command name and the arguments.